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we now see that the format specifier "%. 2f" tells the printf method to print a floating point value (the double, x, in this case) with 2 decimal places. Similarly, had we used "%. 3f", x would have been printed rounded to 3 decimal places.
In Python, to print 2 decimal places we will use str. format() with “{:. 2f}” as string and float as a number. Call print and it will print the float with 2 decimal places.
According to most sources I've found, across multiple languages that use printf specifiers, the %g specifier is supposed to be equivalent to either %f or %e - whichever would produce shorter output for the provided value.
What you want is %.2f, not 2%f.
Also, you might want to replace your %d with a %f ;)
#include <cstdio>
int main()
{
printf("When this number: %f is assigned to 2 dp, it will be: %.2f ", 94.9456, 94.9456);
return 0;
}
This will output:
When this number: 94.945600 is assigned to 2 dp, it will be: 94.95
See here for a full description of the printf formatting options: printf
Use: "%.2f" or variations on that.
See the POSIX spec for an authoritative specification of the printf() format strings. Note that it separates POSIX extras from the core C99 specification. There are some C++ sites which show up in a Google search, but some at least have a dubious reputation, judging from comments seen elsewhere on SO.
Since you're coding in C++, you should probably be avoiding printf() and its relatives.
For %d part refer to this How does this program work? and for decimal places use %.2f
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