Try/Catch block in PHP not catching Exception

Question

I am trying to run this Example #1 from this page: http://php.net/manual/en/language.exceptions.php

<?php function inverse($x) {     if (!$x) {         throw new Exception('Division by zero.');     }     return 1/$x; } try {     echo inverse(5) . "\n";     echo inverse(0) . "\n"; } catch (Exception $e) {     echo 'Caught exception: ',  $e->getMessage(), "\n"; } // Continue execution echo "Hello World\n"; ?> 

However instead of the desired output I get:

0.2 Fatal error: Uncaught exception 'Exception' with message 'Division by zero.'  in xxx: 7 Stack trace: #0 xxx(14): inverse(0) #1 {main} thrown in xxx on line 7 

The developer environment I am using is UniServer 3.5 with PHP 5.2.3

Answer 1

I just had this exact problem where it seemed like I had even copied the name of the exception and yet it didn't catch it. It turned out it was my stupid mistake but I thought I should post my case here in case there is someone else in the same situation.

I had my exception in my namespace called A and the script was in a namespace called B. The problem was that I had A\MyException which equals (in PHP) \B\A\MyException (because my script is in the namespace called B!). All I had to do to fix it was to add backslash (or whatever it's called) to the exception name so it would look like this: \A\MyException

Answer 2

Quite old question, yet...

I had this problem as well (and that's how I found this post) but just simple experiment allowed me to find the solution. Just try changing Exception to \Exception. Worked for me!

EDIT:

As sivann pointed in the comments, using namespace should do the same thing. So simply put use \Exception as Exception; before your class declaration.