PHP cURL HTTP CODE return 0

Question

I dont understand when I echo $httpCode I always get 0, I was expecting 404 when I change $html_brand into a broken url. Is there anything that I miss or do not know of? Thanks.

 //check if url exist $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $html_brand); curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE); $response = curl_exec($ch);  $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);  if ($httpCode == 404) {     echo "The Web Page Cannot Be Found";     return; } curl_close($ch); 

Answer 1

If you connect with the server, then you can get a return code from it, otherwise it will fail and you get a 0. So if you try to connect to "www.google.com/lksdfk" you will get a return code of 400, if you go directly to google.com, you will get 302 (and then 200 if you forward to the next page... well I do because it forwards to google.com.br, so you might not get that), and if you go to "googlecom" you will get a 0 (host no found), so with the last one, there is nobody to send a code back.

Tested using the code below.

<?php  $html_brand = "www.google.com"; $ch = curl_init();  $options = array(     CURLOPT_URL            => $html_brand,     CURLOPT_RETURNTRANSFER => true,     CURLOPT_HEADER         => true,     CURLOPT_FOLLOWLOCATION => true,     CURLOPT_ENCODING       => "",     CURLOPT_AUTOREFERER    => true,     CURLOPT_CONNECTTIMEOUT => 120,     CURLOPT_TIMEOUT        => 120,     CURLOPT_MAXREDIRS      => 10, ); curl_setopt_array( $ch, $options ); $response = curl_exec($ch);  $httpCode = curl_getinfo($ch, CURLINFO_HTTP_CODE);  if ( $httpCode != 200 ){     echo "Return code is {$httpCode} \n"         .curl_error($ch); } else {     echo "<pre>".htmlspecialchars($response)."</pre>"; }  curl_close($ch); 

Answer 2

Try this after curl_exec to see what's the problem:

print curl_error($ch); 

If it's print something like 'malformed' then check your URL format.