Updated for Swift 5.1
Assume the following throwing function:
enum ThrowableError: Error {
case badError(howBad: Int)
}
func doSomething(everythingIsFine: Bool = false) throws -> String {
if everythingIsFine {
return "Everything is ok"
} else {
throw ThrowableError.badError(howBad: 4)
}
}
You have 2 options when you try calling a function that may throw.
You can take responsibility of handling errors by surrounding your call within a do-catch block:
do {
let result = try doSomething()
}
catch ThrowableError.badError(let howBad) {
// Here you know about the error
// Feel free to handle or to re-throw
// 1. Handle
print("Bad Error (How Bad Level: \(howBad)")
// 2. Re-throw
throw ThrowableError.badError(howBad: howBad)
}
Or just try calling the function, and pass the error along to the next caller in the call chain:
func doSomeOtherThing() throws -> Void {
// Not within a do-catch block.
// Any errors will be re-thrown to callers.
let result = try doSomething()
}
What happens when you try to access an implicitly unwrapped optional with a nil inside it? Yes, true, the app will CRASH! Same goes with try! it basically ignores the error chain, and declares a “do or die” situation. If the called function didn’t throw any errors, everything goes fine. But if it failed and threw an error, your application will simply crash.
let result = try! doSomething() // if an error was thrown, CRASH!
A new keyword that was introduced in Xcode 7 beta 6. It returns an optional that unwraps successful values, and catches error by returning nil.
if let result = try? doSomething() {
// doSomething succeeded, and result is unwrapped.
} else {
// Ouch, doSomething() threw an error.
}
Or we can use guard:
guard let result = try? doSomething() else {
// Ouch, doSomething() threw an error.
}
// doSomething succeeded, and result is unwrapped.
One final note here, by using try?
note that you’re discarding the error that took place, as it’s translated to a nil.
Use try? when you’re focusing more on successes and failure, not on why things failed.
You can use the coalescing operator ?? with try? to provide a default value incase of failure:
let result = (try? doSomething()) ?? "Default Value"
print(result) // Default Value
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