I'm learning the Lens package. I must say it's a rather challenging task.
Can someone show me how to traverse a Tree with Zipper from Lens? In particular, how can I write a function that takes a list of roots and allows me to access the branches of the sub-tree?
Suppose I have this tree. If my input is [1, 3]
, the function should allow me access node 10 and 11.
import Control.Lens
import Data.Tree
import Data.Tree.Lens
testTree = Node 1 [ Node 2 [ Node 4 [ Node 6 [], Node 8 [] ],
Node 5 [ Node 7 [], Node 9 [] ] ],
Node 3 [ Node 10 [],
Node 11 [] ]
]
zipperTree = zipper testTree
In addition, how exactly do I use saveTape
and restoreTape
to save the traversal path (to a StateT or IORef)?
edit: I normally experiment in ghci to understand new code so for those like myself I have created a School of Haskell post/page which comes with the below examples but they are editable and runnable.
Think this examples will answer your questions but for expediency I am going to modify a different node. My knowledge of the zipper functions in the lens is rather shallow. It takes a little longer to read and get used to the types in the lens package compared to many other packages, but afterwards it is not bad. I had not used the zipper module or the tree module in the lens package before this post.
The trees do not pretty pretty well with show
so if I have time I will come back and add some pretty printed out put otherwise it is probably key to work in the repl with these examples to see what is happening.
If I want to view the value of the first node, according to the tree lens package this is referred to as the root, then you can:
zipperTree & downward root & view focus
To modify that value and recreate the tree(rezip the tree):
zipperTree & downward root & focus .~ 10 & rezip
If you wanted to move down the branches then you need to use downward branches
. Here is an example that modifies the root of the first branch and rezipx the tree:
zipperTree & downward branches
& fromWithin traverse
& downward root
& focus .~ 5
& rezip
Here I move downward to the list of branchs. I then use fromWithin
use use traverse
to traverse the list, if this was a tuple I could use both
instead.
saveTape
and restoreTape
allow for you to save your position in the zipper so that it can be restored latter.
Save a position:
tape = zipperTree & downward branches
& fromWithin traverse
& downward root
& saveTape
Then to recreate the traversal through the tree I can:
t <- (restoreTape tape testTree)
Then you can use t as the new zipper and modify it as normal:
t & focus .~ 15 & rezip
The tape replays the steps that you took so can work on other trees so the follow would work with the tape as defined above:
testTree2 = Node 1 [ Node 2 [] ]
t2 <- (restoreTape tape testTree2)
t2 & focus .~ 25 & rezip
If you want to modify multiple roots just hold off on reziping the zipper. The following modifies the two roots of testTree2:
zipper testTree2 & downward root
& focus .~ 11
& upward
& downward branches
& fromWithin traverse
& downward root
& focus .~ 111
& rezip
In my experience, you typically don't want a Zipper. In this case you can define a Traversal which will allows you to access subforests given a path of root nodes.
-- Make things a little easier to read
leaf :: a -> Tree a
leaf = return
testForest :: Forest Int
testForest = [ Node 1 [ Node 2 [ Node 4 [ leaf 6, leaf 8]
, Node 5 [ leaf 7, leaf 9]]
, Node 3 [ leaf 10, leaf 11]]]
-- | Handy version of foldr with arguments flipped
foldEndo :: (a -> b -> b) -> [a] -> b -> b
foldEndo f xs z = foldr f z xs
-- | Traverse the subforests under a given path specified by the values of
-- the parent nodes.
path :: Eq a => [a] -> Traversal' (Forest a) (Forest a)
path = foldEndo $ \k -> -- for each key in the list
traverse -- traverse each tree in the forest
. filtered (hasRoot k) -- traverse a tree when the root matches
. branches -- traverse the subforest of the tree
where
hasRoot :: Eq a => a -> Tree a -> Bool
hasRoot k t = k == view root t
-- | Helper function for looking at 'Forest's.
look :: Show a => Forest a -> IO ()
look = putStr . drawForest . (fmap . fmap) show
-- Just show 'path' in action
demo1 = look $ testForest & path [1,3] .~ []
demo2 = look $ testForest & path [1,3] . traverse . root *~ 2
demo3 = look $ testForest ^. path [1,3]
demo4 = [] == testForest ^. path [9,3]
demo5 = traverseOf_ (path [1,3]) print testForest
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