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Tomcat Java Servlet - Initialize Class on Application Startup

I have a class that takes a bit of time to start up (makes some JNI calls and what not), so it is not feasable to initialize this class everytime a page loads. Is it possible to initialize this class on application startup, then access its methods as pages are being served up?

For Example:

I have MyClass. When the application (tomcat) starts up I would like it to initialze my calss as follows:

MyClass myClassInstance = new MyClass("arg1", "arg2");

Then when a page is called, say /testpage, I would like to make calls to myClassInstance:

import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
import MyClass;

public class TestPage extends HttpServlet {

    public void doGet(HttpServletRequest request, HttpServletResponse response) throws IOException, ServletException
    {
        String myResult = myClassInstance.getResult("whatever");

        response.setContentType("text/html");
        PrintWriter out = response.getWriter();
        out.println("<html>");
        out.println("<head>");
        out.println("<title>Test</title>");
        out.println("</head>");
        out.println("<body>");
        out.println("<h1>" +myResult +"</h1>");
        out.println("</body>");
        out.println("</html>");
    }
}

Is this possible?

like image 693
Petey B Avatar asked Jun 01 '11 20:06

Petey B


2 Answers

You have two choices:

  1. Initialize your class in servlet's init() method. You may add <load-on-startup> attribute to make sure your servlet is created at application startup and not on first access.

  2. Add ServletContextListener and use contextInitialized() callback method. Use ServletContext#setAttribute to store created object for future use.

like image 134
Tomasz Nurkiewicz Avatar answered Oct 30 '22 17:10

Tomasz Nurkiewicz


If you want it to happen once for the whole app, and happen before any servlet is run, implement ServletContextListener and put your startup code in contextInitialized(). Then set up your web.xml to specify your class as a listener.

Otherwise, you can do what the other answer says and put it in the init() method of the servlet.

like image 26
QuantumMechanic Avatar answered Oct 30 '22 17:10

QuantumMechanic