I need to calculate the foot of a perpendicular line drawn from a point P to a line segment AB. I need coordinates of point C where PC is perpendicular drawn from point P to line AB.
I found few answers on SO here but the vector product process does not work for me. Here is what I tried:
function nearestPointSegment(a, b, c) {
var t = nearestPointGreatCircle(a,b,c);
return t;
}
function nearestPointGreatCircle(a, b, c) {
var a_cartesian = normalize(Cesium.Cartesian3.fromDegrees(a.x,a.y))
var b_cartesian = normalize(Cesium.Cartesian3.fromDegrees(b.x,b.y))
var c_cartesian = normalize(Cesium.Cartesian3.fromDegrees(c.x,c.y))
var G = vectorProduct(a_cartesian, b_cartesian);
var F = vectorProduct(c_cartesian, G);
var t = vectorProduct(G, F);
t = multiplyByScalar(normalize(t), R);
return fromCartesianToDegrees(t);
}
function vectorProduct(a, b) {
var result = new Object();
result.x = a.y * b.z - a.z * b.y;
result.y = a.z * b.x - a.x * b.z;
result.z = a.x * b.y - a.y * b.x;
return result;
}
function normalize(t) {
var length = Math.sqrt((t.x * t.x) + (t.y * t.y) + (t.z * t.z));
var result = new Object();
result.x = t.x/length;
result.y = t.y/length;
result.z = t.z/length;
return result;
}
function multiplyByScalar(normalize, k) {
var result = new Object();
result.x = normalize.x * k;
result.y = normalize.y * k;
result.z = normalize.z * k;
return result;
}
function fromCartesianToDegrees(pos) {
var carto = Cesium.Ellipsoid.WGS84.cartesianToCartographic(pos);
var lon = Cesium.Math.toDegrees(carto.longitude);
var lat = Cesium.Math.toDegrees(carto.latitude);
return [lon,lat];
}
What I am missing in this?
Here's a vector-based way:
function foot(A, B, P) {
const AB = {
x: B.x - A.x,
y: B.y - A.y
};
const k = ((P.x - A.x) * AB.x + (P.y - A.y) * AB.y) / (AB.x * AB.x + AB.y * AB.y);
return {
x: A.x + k * AB.x,
y: A.y + k * AB.y
};
}
const A = { x: 1, y: 1 };
const B = { x: 4, y: 5 };
const P = { x: 4.5, y: 3 };
const C = foot(A, B, P);
console.log(C);
// perpendicular?
const AB = {
x: B.x - A.x,
y: B.y - A.y
};
const PC = {
x: C.x - P.x,
y: C.y - P.y
};
console.log((AB.x * PC.x + AB.y * PC.y).toFixed(3));
I start with the vector from A to B, A➞B. By multiplying this vector by a scalar k and adding it to point A I can get to any point C on the line AB.
I) C = A + k × A➞B
Next I need to establish the 90° angle, which means the dot product of A➞B and P➞C is zero.
II) A➞B · P➞C = 0
Now solve for k.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With