I’m porting an iOS app to Android, and using Google Maps Android API v2.
The application needs to draw a heatmap overlay onto the map.
So far, it looks like the best option is to use a TileOverlay
and implement a custom TileProvider
. In the method getTile
, my method is given x, y, and zoom, and needs to return a bitmap in the form of a Tile
. So far, so good.
I have an array of heatmap items that I will use to draw radial gradients onto the bitmap, each with a lat/long. I am having trouble with the following two tasks:
Thank you for your help!
UPDATE
Thanks to MaciejGórski's answer below, and marcin's implementation I was able to get the 1st half of my question answered, but I still need help with the 2nd part. To clarify, I need a function to return the x/y coordinates of the tile for a specified lat/long. I've tried reversing the calculations of MaciejGórski's and marcin's answer with no luck.
public static Point fromLatLng(LatLng latlng, int zoom){
int noTiles = (1 << zoom);
double longitudeSpan = 360.0 / noTiles;
double mercator = fromLatitude(latlng.latitude);
int y = ((int)(mercator / 360 * noTiles)) + 180;
int x = (int)(latlng.longitude / longitudeSpan) + 180;
return new Point(x, y);
}
Any help is appreciated!
This worked for me:
double n = Math.pow(2, zoom);
double longitudeMin = x/n * 360 -180;
double lat_rad = Math.atan(Math.sinh(Math.PI * (1 - 2 * y/n)));
double latitudeMin = lat_rad * 180/Math.PI;
double longitudeMax = (x + 1)/n * 360 -180;
lat_rad = Math.atan(Math.sinh(Math.PI * (1 - 2 * (y + 1)/n)));
double latitudeMax = lat_rad * 180/Math.PI;
References: http://wiki.openstreetmap.org/wiki/Slippy_map_tilenames
On zoom level 0, there is only one tile (x=0,y=0). On next zoom level number of tiles are quadrupled (doubled on x and y).
This means on zoom level W
, x may be a value in range <0, 1 << W).
From documentation:
The coordinates of the tiles are measured from the top left (northwest) corner of the map. At zoom level N, the x values of the tile coordinates range from 0 to 2N - 1 and increase from west to east and the y values range from 0 to 2N - 1 and increase from north to south.
You can achieve this using simple calculations.
For longitude this is straightforward :
double longitudeMin = (((double) x) / (1 << zoom)) * 360 - 180;
double longitudeMax = (((double) x + 1) / (1 << zoom)) * 360 - 180;
longitudeMax = Double.longBitsToDouble(Double.doubleToLongBits(longitudeMax) - 1); // adjust
Here x is first scaled into <0,1), then into <-180,180).
The max value is adjusted, so it doesn't overlap with the next area. You may skip this.
For latitude this will be a bit harder, because Google Maps use Mercator projection.
First you scale y just like it was in range <-180,180). Note that the values need to be reversed.
double mercatorMax = 180 - (((double) y) / (1 << zoom)) * 360;
double mercatorMin = 180 - (((double) y + 1) / (1 << zoom)) * 360;
Now you use a magical function that does Mercator projection (from SphericalMercator.java):
public static double toLatitude(double mercator) {
double radians = Math.atan(Math.exp(Math.toRadians(mercator)));
return Math.toDegrees(2 * radians) - 90;
}
latitudeMax = SphericalMercator.toLatitude(mercatorMax);
latitudeMin = SphericalMercator.toLatitude(mercatorMin);
latitudeMin = Double.longBitsToDouble(Double.doubleToLongBits(latitudeMin) + 1);
This was was typed from memory and was not tested in any way, so if there is an error there, please put a comment and I will fix it.
MaciejGórski if you don't mind (if you do, I will remove this post) I compiled your code into ready to use method:
private LatLngBounds boundsOfTile(int x, int y, int zoom) {
int noTiles = (1 << zoom);
double longitudeSpan = 360.0 / noTiles;
double longitudeMin = -180.0 + x * longitudeSpan;
double mercatorMax = 180 - (((double) y) / noTiles) * 360;
double mercatorMin = 180 - (((double) y + 1) / noTiles) * 360;
double latitudeMax = toLatitude(mercatorMax);
double latitudeMin = toLatitude(mercatorMin);
LatLngBounds bounds = new LatLngBounds(new LatLng(latitudeMin, longitudeMin), new LatLng(latitudeMax, longitudeMin + longitudeSpan));
return bounds;
}
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