there. I'm using C# .wpf, and I get this some code from C# source, but I can't use it. is there anything that I must change? or do?
// Delegates to enable async calls for setting controls properties
private delegate void SetTextCallback(System.Windows.Controls.TextBox control, string text);
// Thread safe updating of control's text property
private void SetText(System.Windows.Controls.TextBox control, string text)
{
if (control.InvokeRequired)
{
SetTextCallback d = new SetTextCallback(SetText);
Invoke(d, new object[] { control, text });
}
else
{
control.Text = text;
}
}
As above code, the error is in InvokeRequired
and Invoke
the purpose is, I have a textbox which is content, will increment for each process.
here's the code for the textbox. SetText(currentIterationBox.Text = iteration.ToString());
is there anything wrong with the code?
thank you for any help
EDIT
// Delegates to enable async calls for setting controls properties
private delegate void SetTextCallback(System.Windows.Controls.TextBox control, string text);
// Thread safe updating of control's text property
private void SetText(System.Windows.Controls.TextBox control, string text)
{
if (Dispatcher.CheckAccess())
{
control.Text = text;
}
else
{
SetTextCallback d = new SetTextCallback(SetText);
Dispatcher.Invoke(d, new object[] { control, text });
}
}
You probably took that code from Windows Forms, where every Control has a Invoke
method. In WPF you need to use the Dispatcher
object, accessible through a Dispatcher
property:
if (control.Dispatcher.CheckAccess())
{
control.Text = text;
}
else
{
SetTextCallback d = new SetTextCallback(SetText);
control.Dispatcher.Invoke(d, new object[] { control, text });
}
Additionally, you're not calling SetText
correctly. It takes two arguments, which in C# are separated with commas, not with equal signs:
SetText(currentIterationBox.Text, iteration.ToString());
In WPF you dont use Control.Invoke but Dispatcher.Invoke like this:
Dispatcher.Invoke((Action)delegate(){
// your code
});
Use
Dispatcher.CheckAccess()
to check first.
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