Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

The input is not a valid Base-64 string as it contains a non-base 64 character

Tags:

c#

file-io

base64

People also ask

What are valid base 64 characters?

Base64 only contains A–Z , a–z , 0–9 , + , / and = . So the list of characters not to be used is: all possible characters minus the ones mentioned above. For special purposes .

What is valid Base64 string?

It's pretty easy to recognize a Base64 string, as it will only be composed of characters 'A'..'Z', 'a'..'z', '0'..'9', '+', '/' and it is often padded at the end with up to three '=', to make the length a multiple of 4.


Check if your image data contains some header information at the beginning:

imageCode = "data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAMgAAABkC...

This will cause the above error.

Just remove everything in front of and including the first comma, and you good to go.

imageCode = "iVBORw0KGgoAAAANSUhEUgAAAMgAAABkC...

Very possibly it's getting converted to a modified Base64, where the + and / characters are changed to - and _. See http://en.wikipedia.org/wiki/Base64#Implementations_and_history

If that's the case, you need to change it back:

string converted = base64String.Replace('-', '+');
converted = converted.Replace('_', '/');

We can remove unnecessary string input in front of the value.

string convert = hdnImage.Replace("data:image/png;base64,", String.Empty);

byte[] image64 = Convert.FromBase64String(convert);

Remove the unnecessary string through Regex

Regex regex=new Regex(@"^[\w/\:.-]+;base64,");
base64File=regex.Replace(base64File,string.Empty);