Using .NET 4 you can use something as simple as:
private void Control_DoubleClick(object sender, EventArgs e)
{
if (ModifierKeys.HasFlag(Keys.Control))
{
MessageBox.Show("Ctrl is pressed!");
}
}
If you're not using .NET 4, then the availability of Enum.HasFlag
is revoked, but to achieve the same result in previous versions:
private void CustomFormControl_DoubleClick(object sender, EventArgs e)
{
if ((ModifierKeys & Keys.Control) == Keys.Control)
{
MessageBox.Show("Ctrl is pressed!");
}
}
Just for completeness... ModifierKeys
is a static property of Control
, so you can test it even when you are not directly in an event handler:
public static bool IsControlDown()
{
return (Control.ModifierKeys & Keys.Control) == Keys.Control;
}
This isn't really an answer to the question at hand, but I needed to do this in a console application and the detail was a little different.
I had to add references to WindowsBase
and PresentationFramework
, and at that point I could do:
if (System.Windows.Input.Keyboard.Modifiers == ModifierKeys.Control)
blah
Just adding this here in case someone else is doing something similar.
Even this also
private void Control_MouseDoubleClick(object sender, MouseEventArgs e)
{
if (ModifierKeys == Keys.Control)
MessageBox.Show("with CTRL");
}
This works for me:
if(Keyboard.IsKeyDown(Key.LeftCtrl))
{}
And add references to PresentationCore and WindowsBase
The same soneone said above, but comparing as different than zero, which should be a little faster and use less instructions on most architectures:
public static bool IsControlDown()
{
return (Control.ModifierKeys & Keys.Control) != 0;
}
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