Ternary operator implicit cast to base class

Question

Consider this piece of code:

struct Base {     int x; };  struct Bar : Base {     int y; };  struct Foo : Base {     int z; };  Bar* bar = new Bar; Foo* foo = new Foo;  Base* returnBase() {     Base* obj = !bar ? foo : bar;     return obj; }  int main() {     returnBase();     return 0; } 

This doesn't work under Clang or GCC, giving me :

error: conditional expression between distinct pointer types ‘Foo*’ and ‘Bar*’ lacks a cast Base* obj = !bar ? foo : bar;

Which means for it to compile I have to change the code to :

Base* obj = !bar ? static_cast<Base*>(foo) : bar; 

Since an implicit cast to a Base* exists, what is preventing the compiler from doing so?

In other words, why does Base* obj = foo; work without a cast but using the ?: operator doesn't? Is it because it's not clear that I want to use the Base part?

Answer 1

Quoting from C++ standard draft N4296, Section 5.16 Conditional operator, Paragraph 6.3:

• One or both of the second and third operands have pointer type; pointer conversions (4.10) and qualification conversions (4.4) are performed to bring them to their composite pointer type (Clause 5). The result is of the composite pointer type.

Section 5 Expressions, Paragraph 13.8 and 13.9:

The composite pointer type of two operands p1 and p2 having types T1 and T2, respectively, where at least one is a pointer or pointer to member type or std::nullptr_t, is:

• if T1 and T2 are similar types (4.4), the cv-combined type of T1 and T2;
• otherwise, a program that necessitates the determination of a composite pointer type is ill-formed.

Note: I copied 5/13.8 here just to show you that it doesn't hit. What's actually in effect is 5/13.9, "the program is ill-formed".

And Section 4.10 Pointer conversions, Paragraph 3:

A prvalue of type “pointer to cv D”, where D is a class type, can be converted to a prvalue of type “pointer to cv B”, where B is a base class (Clause 10) of D. If B is an inaccessible (Clause 11) or ambiguous (10.2) base class of D, a program that necessitates this conversion is ill-formed. The result of the conversion is a pointer to the base class subobject of the derived class object. The null pointer value is converted to the null pointer value of the destination type.

So, it doesn't matter (at all) that both Foo and Bar are derived from one same base class. It only matters that a pointer to Foo and a pointer to Bar are not convertible to each other (no inheritance relationship).