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Is there a (POSIX command line) way to print all of a file EXCEPT the last n lines? Use case being, I will have multiple files of unknown size, all of which contain a boilerplate footer of a known size, which I want to remove. I was wondering if there is already a utility that does this before writing it myself.
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tail [OPTION]... [ Tail is a command which prints the last few number of lines (10 lines by default) of a certain file, then terminates. Example 1: By default “tail” prints the last 10 lines of a file, then exits.
head is a basic opposite of tail in relation to what part of the file operations are performed on. By default, head will read the first 10 lines of a file.
To display the last part of the file, we use the tail command in the Linux system. The tail command is used to display the end of a text file or piped data in the Linux operating system. By default, it displays the last 10 lines of its input to the standard output. It is also complementary of the head command.
In sed, $ indicates the last line, and $p tells to print(p) the last line($) only. 4. Another option in sed is to delete(d) all the lines other than(!) the last line($) which in turn prints only the last line.
Most versions of head(1) - GNU derived, in particular, but not BSD derived - have a feature to do this. It will show the top of the file except the end if you use a negative number for the number of lines to print.
Like so:
head -n -10 textfile If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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