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I have been staring at this code for hours now and I cannot figure out where my mistake is. I know this syntax error usually comes up because of some missing or out of place curly brace or some issue with single/double quotes and I'm not sure there is one anywhere in my code. I am only trying to fix my syntax right now so I can get the code to completely compile. Any help would be much appreciated. Here is my code:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<title>Add to and Read from the Database</title>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
</head>
<body>
<?php
function print_form() {
echo <<<END
<form action="$_SERVER[PHP_SELF]" method="post">
<h3>Please put your comments below.</h3>
<input type="hidden" name="stage" value="process" >
<p>Name:</p>
<input type="text" size="30" name="WholeName" />
<p>Comment:</p>
<input type="text" size="200" name="Comment" />
<input type ="submit" value ="Submit" >
</form>
END;
}
function process_form() {
print "<p>adding comment...</p>";
$Name = $_POST['WholeName'];
$Comment = $_POST['Comment'];
if( preg_match("^[a-zA-Z]+$", $Name)) {
if( preg_match("^[a-zA-Z0-9]_\-\'[.?!]+$", $Comment)) {
$sql = "insert into comments1 values (
'$Name',
'$Comment')";
$result = mysql_query($sql) or die("Mysql query failed");
} else {
print "invalid name";
}
} else {
print "invalid characters";
}
}
$db = mysql_connect("", "", "");
if (!$db) {
print "Error - Could not connect to mysql";
exit;
}
$er = mysql_select_db("");
if (!$er) {
print "Error - Could not connect to comments1 database";
exit;
}
if (isset($_POST['stage']) && ('process' == $_POST['stage'])) {
process_form();
} else {
print_form();
}
?>
</body>
</html>
507
I stumbled on this question as I had the same error. Mine was due to a slightly different problem and since I resolved it on my own I thought it useful to share here. Original code with issue:
$comment = "$_POST['comment']";
Because of the enclosing double-quotes, the index is not dereferenced properly leading to the assignment error. In my case I chose to fix it like this:
$comment = "$_POST[comment]";
but dropping either pair of quotes works; it's a matter of style I suppose :)
111
Your problem is that you're not closing your HEREDOC correctly. The line containing END; must not contain any whitespace afterwards.
32
You have extra spaces after END; that cause the heredoc not terminated.
22
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