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SynchronizationContext.Post to UI Method

I'm working with web services so its necessary for me to extend session length/reconnect and get large datasets back etc. Sometimes this can be lengthy so I wanted it in an separate thread that updates the UI asynchronously.

I can't seem to get my head around using the synchronizationContext to invoke a method on my UI thread. I have it whereby I have passed my UIThread context to my thread and now I want to update some labels etc on UI Thread. I've read tons of posts but none seem to explain how to simply pass some parameters back to a method, or maybe they do but i'm too tired/stupid to have seen it.

//On main UI Thread

public void updateConnStatus(string conn_name, bool connected)
{
        switch (conn_name)
        {
            case "Conn" : if (connected == true){ //do something} break;

//on separate Thread

uiContext.Post( //something to do with delegates in here that eludes me );

if someone could simply explain how I link the sendOrPostCallBack to the original method I would be very grateful.

Thanks

Edit:

I managed to get the code to run and try to fire the event, it populates my custom eventArgs okay but either its saying that updateUIConnStatus has not been instantiated, needs more investigation :o

public void updateUIThread(string conn, bool connected)
    {
       uiContext.Post(new SendOrPostCallback((o) => { updateConnStatus(this, new MyEventArgs<String, Boolean>(conn, connected)); }), null);
    }

public class MyEventArgs<T, U> : EventArgs
    {
        private T _val1; private U _val2;
        public  MyEventArgs(T value1, U value2) { _val1 = value1; _val2 = value2; }
        public T val1 { get { return _val1;} }
        public U val2 { get {return _val2;} }
    }

public event EventHandler<MyEventArgs<String, Boolean>> updateConnStatus = Delegate {};

//on UI Thread Now

 public void updateConnStatus(object sender, MyEventArgs<String,Boolean> e)
    {
        switch (e.val1)
        {
            case "Conn1" :
                if (e.val2 == true)
                {
like image 821
Peter Lea Avatar asked Aug 19 '12 18:08

Peter Lea


2 Answers

You need a delegate of type SendOrPostCallback. Which is pretty awkward, it only takes a single argument of type object. You definitely ought to look at the Task<> class available in .NET 4 to make this easier. Or use a lambda, like this:

        string conn_name = "foo";
        uiContext.Post(new SendOrPostCallback((o) => {
            updateConnStatus(conn_name, true);
        }), null);

The code between the { braces } executes on the UI thread.

like image 62
Hans Passant Avatar answered Oct 14 '22 12:10

Hans Passant


Typically you are creating instances of your types (e.g. ViewModels) on the UI thread, so you can just save the SynchronizationContext or the TaskScheduler (preferable IMHO) to a private field and then compare it when needed...

private readonly SynchronizationContext _syncContext = SynchronizationContext.Current;
private readonly TaskScheduler _scheduler = TaskScheduler.Current;

void OnSomeEvent(object sender, EventArgs e)
{
    if (_syncContext != SynchronizationContext.Current)
    {
        // Use Send if you need to get something done as soon as possible.
        // We'll be polite by using Post to wait our turn in the queue.
        _syncContext.Post(o => DoSomething(), null);
        return;
    }
    // Call directly if we are already on the UI thread
    DoSomething();
}

void OnSomeOtherEvent(object sender, MyEventArgs e)
{
    var arg1 = e.Arg1; // "Hello "
    var arg2 = e.Arg2; // {"World", "!"};

    // Process args in the background, and then show the result to the user...
    // NOTE: We don't even need to check the context because we are passing
    // the appropriate scheduler to the continuation that shows a MessageBox.

    Task<string>.Factory.StartNew(() => ReturnSomething(arg1, arg2))
        .ContinueWith(t => MessageBox.Show(t.Result), _scheduler);
}

void DoSomething() { MessageBox.Show("Hello World!"); }

string ReturnSomething(string s, IEnumerable<string> list)
{
    return s + list.Aggregate((c, n) => c + n);
}
like image 23
Ben Stabile Avatar answered Oct 14 '22 10:10

Ben Stabile