Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

Symfony2 create own encoder for storing password

I'm new to Symfony2 and I have maybe a simple question about encoding my user passwords in my DB.

I'd like to encode and store in DB my users' password that way:

encoded_password = salt . sha1 ( salt . raw_password )

I've found various encoders (sha1, sha512, plaintext), I saw that with plaintext I have in my DB raw_password{salt} but I'm still not comfortable with signin/login/getSalt() method in Symfony2.

If you could give me a lift on that (please, assume I do not want to use an existing bundle for UserManagement, I'd like to make my own) it would be AWESOME!

Thanks

EDIT:

I could do that in my signinAction():

$salt = substr(md5(time()),0,10);
$pwd = $encoder->encodePassword($user->getPassword(), $salt);
$user->setPassword($salt.$pwd);

I could do that in my getSalt():

return substr($this->password,0,10);

But I currently have only that in my loginAction(): (see here: http://symfony.com/doc/current/book/security.html)

// src/Acme/SecurityBundle/Controller/Main;
namespace Acme\SecurityBundle\Controller;

use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\Security\Core\SecurityContext;

class SecurityController extends Controller
{
    public function loginAction()
    {
        $request = $this->getRequest();
        $session = $request->getSession();

        // get the login error if there is one
        if ($request->attributes->has(SecurityContext::AUTHENTICATION_ERROR)) {
            $error = $request->attributes->get(SecurityContext::AUTHENTICATION_ERROR);
        } else {
            $error = $session->get(SecurityContext::AUTHENTICATION_ERROR);
        }

        return $this->render('AcmeSecurityBundle:Security:login.html.twig', array(
            // last username entered by the user
            'last_username' => $session->get(SecurityContext::LAST_USERNAME),
            'error'         => $error,
        ));
    }
}

How can I tell Symfony2 to check the password during the login action the way I need? (curently doing encode(password,salt) and not salt.encode(password,salt)

like image 313
guillaumepotier Avatar asked Oct 24 '11 16:10

guillaumepotier


1 Answers

To make it simple: you have to create and add a new Service, add it to your bundle and specity that the User class will use it. First you have to implement your own password encoder:

namespace Acme\TestBundle\Service;

use Symfony\Component\Security\Core\Encoder\PasswordEncoderInterface;

class Sha256Salted implements PasswordEncoderInterface
{

    public function encodePassword($raw, $salt)
    {
        return hash('sha256', $salt . $raw); // Custom function for password encrypt
    }

    public function isPasswordValid($encoded, $raw, $salt)
    {
        return $encoded === $this->encodePassword($raw, $salt);
    }

}

Then you'll add the service definition and you want to specify to use your custom encoder for the class User. In TestBundle/Resources/config/services.yml you add custom encoder:

services:
    sha256salted_encoder:
        class: Acme\TestBundle\Service\Sha256Salted

and in app/config/security.yml you can therefore specify your custom class as default encoder (for Acme\TestBundle\Entity\User class):

 encoders:
   Acme\TestBundle\Entity\User:
     id: acme.test.sha256salted_encoder

Of course, salt plays a central role in password encryption. Salt is unique and is stored for each user. The class User can be auto-generated using YAML annotations (table should - of course - contain fields username, password, salt and so on) and should implement UserInterface.

Finally you can use it (controller code) when you have to create a new Acme\TestBundle\Entity\User:

// Add a new User
$user = new User();
$user->setUsername = 'username';
$user->setSalt(uniqid(mt_rand())); // Unique salt for user

// Set encrypted password
$encoder = $this->container->get('acme.test.sha256salted_encoder')
  ->getEncoder($user);
$password = $encoder->encodePassword('MyPass', $user->getSalt());
$user->setPassword($password);
like image 68
gremo Avatar answered Oct 05 '22 04:10

gremo