i have an admin generator for the folowing model:
#schema.yml
Author:
columns:
name: { type: string(255), notnull: true }
Book:
columns:
authorId: { type: integer, notnull: true }
title: { type: string(512), notnull: true }
content: { type: string(512), notnull: true }
relations:
Author: { onDelete: CASCADE, local: authorId, foreign: id, foreignAlias: Books}
I have gererated 2 pages with corresponding with each table
php symfony doctrine:generate-admin backend Author
php symfony doctrine:generate-admin backend Book
Now i want in the author view a link to his books. What is the best way to do that ? My try is a custom link that pre-selects filters, but i dont know how to do that.
#generator.yml for Author
# ...
config:
actions: ~
fields:
list:
display: [id, name, _booksLink]
filter: ~
form: ~
edit: ~
new: ~
and
<!-- modules/author/templates/_booksLink.php -->
<a href="<?= link_to('book?author_id='.$author->getId()) ?>"><!-- how to select filter? -->
See <?= $author->getName() ?> books
</a>
Thanks
This lecture answers your question (slide 39 and 40): http://www.slideshare.net/jcleveley/working-with-the-admin-generator
in your actions.class php add:
class AuthorActions extends AutoAuthorActions
{
public function executeViewBooks($request) {
$this->getUser()->setAttribute( 'book.filters',
array('authorId' => $request->getParameter('id')), 'admin_module' );
$this->redirect($this->generateUrl('book'));
}
}
Note about the case: The field name matches the case defined in the schema. Eg: if you have authorId
in the schema, you must write authorId
in the function above (line 5). If you have author_id
in the schema, you must write author_id
in the function. Also, The module names are always lowercase with underscores (eg: schema : MyBooks -> module name: my_books
).
In your generator.yml
list:
object_actions:
_edit: ~
_delete: ~
viewPhones: { label: View books, action: viewBooks }
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With