SwiftUI get Screen size in multiplateform

Question

Actually, i used in my ContentView.swift file

UIScreen.main.bounds.size.width 

to get width screen's size. Unfortunatelly, i can't used this with an MacOS target because it need NSScreen

NSScreen.main.bounds.size.width

Is there any generic Screen to get the screen size?

Answer 1

What I did, to solve this is to create a class with platform conditional.

class SGConvenience{
    #if os(watchOS)
    static var deviceWidth:CGFloat = WKInterfaceDevice.current().screenBounds.size.width
    #elseif os(iOS)
    static var deviceWidth:CGFloat = UIScreen.main.bounds.size.width
    #elseif os(macOS)
    static var deviceWidth:CGFloat? = NSScreen.main?.visibleFrame.size.width // You could implement this to force a CGFloat and get the full device screen size width regardless of the window size with .frame.size.width
    #endif
}

Then I simply call SGConvenience.deviceWidth when needed

Answer 2

i prefer the extension version:

// MARK UIScreen+size.swift

import UIKit

extension UIScreen
{
#if os(watchOS)
    static let screenSize = WKInterfaceDevice.current().screenBounds.size
    static let screenWidth = screenSize.width
    static let screenHeight = screenSize.height
#elseif os(iOS) || os(tvOS)
    static let screenSize = UIScreen.main.nativeBounds.size
    static let screenWidth = screenSize.width
    static let screenHeight = screenSize.height
#elseif os(macOS)
    static let screenSize = NSScreen.main?.visibleFrame.size
    static let screenWidth = screenSize.width
    static let screenHeight = screenSize.height
#endif
    static let middleOfScreen = CGPoint(x: screenWidth / 2, y: screenHeight / 2)
}

and use it like this:

let screenWidth = UIScreen.screenWidth
let middlePointY = UIScreen.middleOfScreen.y