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Swift equivalent of Array.componentsJoinedByString?

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swift

xcode6

In Objective-C we can call componentsJoinedByString to produce a string with each element of the array separated by the supplied string. While Swift has a componentsSeparatedByString method on String, there doesn't appear to be the inverse of this on Array:

'Array<String>' does not have a member named 'componentsJoinedByString' 

What is the inverse of componentsSeparatedByString in Swift?

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devios1 Avatar asked Jul 13 '14 21:07

devios1


2 Answers

Swift 3.0:

Similar to Swift 2.0, but API renaming has renamed joinWithSeparator to joined(separator:).

let joinedString = ["1", "2", "3", "4", "5"].joined(separator: ", ")  // joinedString: String = "1, 2, 3, 4, 5"  

See Sequence.join(separator:) for more information.

Swift 2.0:

You can use the joinWithSeparator method on SequenceType to join an array of strings with a string separator.

let joinedString = ["1", "2", "3", "4", "5"].joinWithSeparator(", ")  // joinedString: String = "1, 2, 3, 4, 5"  

See SequenceType.joinWithSeparator(_:) for more information.

Swift 1.0:

You can use the join standard library function on String to join an array of strings with a string.

let joinedString = ", ".join(["1", "2", "3", "4", "5"])  // joinedString: String = "1, 2, 3, 4, 5"  

Or if you'd rather, you can use the global standard library function:

let joinedString = join(", ", ["1", "2", "3", "4", "5"])  // joinedString: String = "1, 2, 3, 4, 5" 
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Jack Lawrence Avatar answered Sep 22 '22 08:09

Jack Lawrence


The componentsJoinedByString is still available on NSArray, but not on Swift Arrays. You can bridge back and forth though.

var nsarr = ["a", "b", "c"] as NSArray var str = nsarr.componentsJoinedByString(",") 
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Connor Avatar answered Sep 23 '22 08:09

Connor