Swift Double is Not Convertible to CGFloat

Question

I'm trying to draw a simple circle when I get to the following line I get the error "Double is Not Convertable to CGFloat under the startAngle = 0.0

path.addArcWithCenter(center, radius: radius, startAngle: 0.0, endAngle: Float(M_PI) * 2.0, clockwise: true) 

How do I "cast" 0.0 to make it CGFloat in Swift?

The complete function I am writing:

func drawCircle() {     // Drawing code     var bounds:CGRect = secondView.bounds     var center = CGPoint()     center.x = bounds.origin.x + bounds.size.width / 2.0     center.y = bounds.origin.y + bounds.size.height / 2.0     var radius = (min(bounds.size.width, bounds.size.height) / 2.0)     var path:UIBezierPath = UIBezierPath()     path.addArcWithCenter(center, radius: radius, startAngle: CGFloat(0.0), endAngle: Float(M_PI) * 2.0, clockwise: true)     path.stroke()     } 

Answer 1

Convert the values that need to be CGFloat to a CGFloat.

path.addArcWithCenter(center, radius: CGFloat(radius), startAngle: CGFloat(0.0), endAngle: CGFloat(M_PI) * 2.0, clockwise: true) 

startAngle probably shouldn't need to be converted though if you're just passing a literal. Also note that this isn't a C style cast, but actually converting between different Swift Types.

Edit: Looking at your whole function, this works.

func drawCircle() {         // Drawing code         var bounds:CGRect = self.view.bounds         var center = CGPoint()         center.x = bounds.origin.x + bounds.size.width / 2.0         center.y = bounds.origin.y + bounds.size.height / 2.0         var radius = (min(bounds.size.width, bounds.size.height) / 2.0)         var path:UIBezierPath = UIBezierPath()         path.addArcWithCenter(center, radius: CGFloat(radius), startAngle: CGFloat(0.0), endAngle: CGFloat(Float(M_PI) * 2.0), clockwise: true)         path.stroke()         }