There is a code of simple program. In constructor, super()
is called without extends to the super class, I can not understand what will does this in this situation?
public class Student {
private String name;
private int rollNum;
Student(String name,int rollNum){
super(); //I can not understand why super keyword here.
this.name=name;
this.rollNum=rollNum;
}
public static void main(String[] args) {
Student s1 = new Student("A",1);
Student s2 = new Student("A",1);
System.out.println(s1.equals(s2));
}
}
Every class that doesn't explicitly extend another class implicitly extends java.lang.Object
. So super()
simply calls the no-arg constructor of Object.
Note that this explicit call is unnecessary since the compiler would add it for you. You only need to add a super()
call in a constructor when you want to invoke a superclass constructor with arguments.
There is not need to add
super()
because it is by default added.
It will call Object
class's default constructor because in JAVA every class extends Object
by default.
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