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I try to call a shellscript via the subprocess module in Python 2.6.
import subprocess
shellFile = open("linksNetCdf.txt", "r")
for row in shellFile:
subprocess.call([str(row)])
My filenames have a length ranging between 400 and 430 characters. When calling the script I get the error:
File "/usr/lib64/python2.6/subprocess.py", line 444, in call
return Popen(*popenargs, **kwargs).wait()
File "/usr/lib64/python2.6/subprocess.py", line 595, in __init__
errread, errwrite)
File "/usr/lib64/python2.6/subprocess.py", line 1106, in _execute_child
raise child_exception
OSError: [Errno 36] File name too long
An example of the lines within linksNetCdf.txt is
./ShellScript 'Title' 'Sometehing else' 'InfoInfo' 'MoreInformation' inputfiile outputfile.txt 3 2
Any ideas how to still run the script?
948
The subprocess module defines one class, Popen and a few wrapper functions that use that class. The constructor for Popen takes arguments to set up the new process so the parent can communicate with it via pipes. It provides all of the functionality of the other modules and functions it replaces, and more.
After reading the docs, I came to know that shell=True means executing the code through the shell. So that means in absence, the process is directly started.
Most of your interaction with the Python subprocess module will be via the run() function. This blocking function will start a process and wait until the new process exits before moving on.
subprocess. check_call() gets the final return value from the script, and 0 generally means "the script completed successfully".
You need to tell subprocess to execute the line as full command including arguments, not just one program.
This is done by passing shell=True to call
import subprocess
cmd = "ls " + "/tmp/ " * 30
subprocess.call(cmd, shell=True)
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