I am currently using a C++ IDE for something that will need to work on C, and wanted to make sure that I won't have problems with this later on. After making the struct below:
typedef struct test {
int a;
int b;
};
I then create an instance of it using
test my_test;
then stuff like my_test.a = 5
, etc... and this works fine in my VStudio C++.
Is this going to work on gcc
later on?
I read the related questions that popped up (I see I am not the first person with this kind of question, either) but no one seemed to use the way I did.
In fact, what is the difference between typedef struct {//stuff} test;
and my version?
typedef struct THIS_IS_A_TAG
{
int a;
int b;
} THIS_IS_A_TYPEDEF;
THIS_IS_A_TYPEDEF object1; // declare an object. C:Ok, C++:Ok
struct THIS_IS_A_TAG object2; // declare another object. C:Ok, C++:Ok
THIS_IS_A_TAG object3; // declare another object. C:Not Ok, C++:Ok
The reason for the typedef is because C programmers would like to be able to do that third thing, but they can't.
The difference between:
struct Name {};
And
typedef struct Name {} Name;
Is that, in C, you need to use:
struct Name instance_name;
With the former, whereas with the latter you may do:
Name instance_name;
In C++, it is not necessary to repeat the struct
keyword in either case. Note that your example in which you create a typedef with no name (i.e. typedef struct Name{};
) is non-standard AFAIK (if you use the keyword typedef
, then you need to supply an alias to which to typedef that name).
As for the last variation:
typedef struct { /* ... */ } Name;
The code above creates an unnamed struct that is aliased to Name. You would use such a struct just the same way you would with typedef struct Name { /* ... */ } Name;
, however compilers often emit the name of the struct (not the alias), and so you may get better error messages involving the struct if you give it a name and typedef that as opposed to typedef'ing an anonymous struct.
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