Code for converting a string to dateTime$date = strtotime ( $input ); echo date ( 'd/M/Y h:i:s' , $date );
strtotime expects a "English textual datetime" (according to the manual), which Y-D-M is not. Any time strtotime returns false, it simply doesn't understand your string, which in this application is expected.
If you want to use the PHP function strtotime to add or subtract a number of days, weeks, months or years from a date other than the current time, you can do it by passing the second optional parameter to the strtotime() function, or by adding it into the string which defines the time to parse.
The strtotime() function parses an English textual datetime into a Unix timestamp (the number of seconds since January 1 1970 00:00:00 GMT). Note: If the year is specified in a two-digit format, values between 0-69 are mapped to 2000-2069 and values between 70-100 are mapped to 1970-2000.
Here is the simplified solution:
$date = '25/05/2010';
$date = str_replace('/', '-', $date);
echo date('Y-m-d', strtotime($date));
Result:
2010-05-25
The strtotime
documentation reads:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
You can parse dates from a custom format (as of PHP 5.3) with DateTime::createFromFormat
$timestamp = DateTime::createFromFormat('!d/m/Y', '23/05/2010')->getTimestamp();
(Aside: The !
is used to reset non-specified values to the Unix timestamp, ie. the time will be midnight.)
If you do not want to (or cannot) use PHP 5.3, then a full list of available date/time formats which strtotime accepts is listed on the Date Formats manual page. That page more thoroughly describes the fact that m/d/Y
is inferred over d/m/Y
(but you can, as mentioned in the answers here, use d-m-Y
, d.m.Y
or d\tm\tY
).
In the past, I've also resorted to the quicky str_replace
mentioned in another answer, as well as self-parsing the date string into another format like
$subject = '23/05/2010';
$formatted = vsprintf('%3$04d/%2$02d/%1$02d', sscanf($subject,'%02d/%02d/%04d'));
$timestamp = strtotime($formatted);
This is a good solution to many problems:
function datetotime ($date, $format = 'YYYY-MM-DD') {
if ($format == 'YYYY-MM-DD') list($year, $month, $day) = explode('-', $date);
if ($format == 'YYYY/MM/DD') list($year, $month, $day) = explode('/', $date);
if ($format == 'YYYY.MM.DD') list($year, $month, $day) = explode('.', $date);
if ($format == 'DD-MM-YYYY') list($day, $month, $year) = explode('-', $date);
if ($format == 'DD/MM/YYYY') list($day, $month, $year) = explode('/', $date);
if ($format == 'DD.MM.YYYY') list($day, $month, $year) = explode('.', $date);
if ($format == 'MM-DD-YYYY') list($month, $day, $year) = explode('-', $date);
if ($format == 'MM/DD/YYYY') list($month, $day, $year) = explode('/', $date);
if ($format == 'MM.DD.YYYY') list($month, $day, $year) = explode('.', $date);
return mktime(0, 0, 0, $month, $day, $year);
}
From the STRTOTIME writeup Note:
Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.
It is as simple as that.
$srchDate = date_format(date_create_from_format('d/m/Y', $srchDate), 'Y/m/d');
This will work for you. You convert the String into a custom date format where you can specify to PHP what the original format of the String is that had been given to it. Now that it is a date format, you can convert it to PHP's default date format, which is the same that is used by MySQL.
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