How do I create a copy of an object in PHP?

Question

In PHP 5+ objects are passed by reference. In PHP 4 they are passed by value (that's why it had runtime pass by reference, which became deprecated).

You can use the 'clone' operator in PHP5 to copy objects:

$objectB = clone $objectA;

Also, it's just objects that are passed by reference, not everything as you've said in your question...

The answers are commonly found in Java books.

1. cloning: If you don't override clone method, the default behavior is shallow copy. If your objects have only primitive member variables, it's totally ok. But in a typeless language with another object as member variables, it's a headache.

2. serialization/deserialization

$new_object = unserialize(serialize($your_object))

This achieves deep copy with a heavy cost depending on the complexity of the object.

According to previous comment, if you have another object as a member variable, do following:

class MyClass {
  private $someObject;

  public function __construct() {
    $this->someObject = new SomeClass();
  }

  public function __clone() {
    $this->someObject = clone $this->someObject;
  }

}

Now you can do cloning:

$bar = new MyClass();
$foo = clone $bar;

According to the docs (http://ca3.php.net/language.oop5.cloning):

$a = clone $b;

Just to clarify PHP uses copy on write, so basically everything is a reference until you modify it, but for objects you need to use clone and the __clone() magic method like in the accepted answer.

This code help clone methods

class Foo{

    private $run=10;
    public $foo=array(2,array(2,8));
    public function hoo(){return 5;}


    public function __clone(){

        $this->boo=function(){$this->hoo();};

    }
}
$obj=new Foo;

$news=  clone $obj;
var_dump($news->hoo());