Menu
I'm trying to use
"value1:value2::value3".split(":");
Problem is that I want it to include the blank results.
It returns: [value1, value2, value3]
It should be: [value1, value2, , value3]
Does anyone know the regexp to fix this?
Ok I found cause of problem. I'm actually reading a text file and it contains this line:
123:;~\&:ST02:M:test:M:4540145::type;12:51253:D:2.2:567766::AL:::::::2.2b
When I process this line reading the text file it produces the erroneous result mentioned above, which is it doesn't include any empty results in cases like this: :::::.
But when I use the above line in a test program it doesn't compile and I get a "invalid escape sequence". I think its because of the "\&".
Is there a workaround to this problem by using a regular expression?
789
Using split()If the string and separator are both empty strings, an empty array is returned.
If the delimiter is an empty string, the split() method will return an array of elements, one element for each character of string. If you specify an empty string for string, the split() method will return an empty string and not an array of strings.
split(CharSequence input, int limit) . The return value comes from a non-null ArrayList on which toArray is called. toArray does not return null: in the event of an empty list you'll get an empty array back. So in the end, no, you don't have to check for null.
The split() function returns the strings as a list.
split does include empty matches in the result, have a look at the docs here. However, by default, trailing empty strings (those at the end of the array) are discarded. If you want to include these as well, try split(":", -1).
139
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
