strcpy vs. memcpy

Question

What is the difference between memcpy() and strcpy()? I tried to find it with the help of a program but both are giving the same output.

int main() {     char s[5]={'s','a','\0','c','h'};     char p[5];     char t[5];     strcpy(p,s);     memcpy(t,s,5);     printf("sachin p is [%s], t is [%s]",p,t);     return 0; } 

Output

sachin p is [sa], t is [sa] 

Answer 1

what could be done to see this effect

Compile and run this code:

void dump5(char *str);  int main() {     char s[5]={'s','a','\0','c','h'};      char membuff[5];      char strbuff[5];     memset(membuff, 0, 5); // init both buffers to nulls     memset(strbuff, 0, 5);      strcpy(strbuff,s);     memcpy(membuff,s,5);      dump5(membuff); // show what happened     dump5(strbuff);      return 0; }  void dump5(char *str) {     char *p = str;     for (int n = 0; n < 5; ++n)     {         printf("%2.2x ", *p);         ++p;     }      printf("\t");      p = str;     for (int n = 0; n < 5; ++n)     {         printf("%c", *p ? *p : ' ');         ++p;     }      printf("\n", str); } 

It will produce this output:

73 61 00 63 68  sa ch 73 61 00 00 00  sa 

You can see that the "ch" was copied by memcpy(), but not strcpy().