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Xcode - Warning: Implicit declaration of function is invalid in C99

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c

xcode

Getting a warning : Implicit declaration of function 'Fibonacci' is invalid in C99. What's wrong?

#include <stdio.h>  int main(int argc, const char * argv[]) {     int input;     printf("Please give me a number : ");     scanf("%d", &input);     getchar();     printf("The fibonacci number of %d is : %d", input, Fibonacci(input)); //!!!  }/* main */  int Fibonacci(int number) {     if(number<=1){         return number;     }else{         int F = 0;         int VV = 0;         int V = 1;         for (int I=2; I<=getal; I++) {             F = VV+V;             VV = V;             V = F;         }         return F;     } }/*Fibonacci*/ 
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CodingUpStream Avatar asked Apr 06 '13 10:04

CodingUpStream


People also ask

What does implicit declaration of function is invalid in c99 mean?

implicit declaration of function means you do not have Prototypes for your functions. You should have a Prototype before the function is used. "call the block" I assume your Blocks are functions. 9/30/2020.

What is implicit declaration error in C?

Such an 'implicit declaration' is really an oversight or error by the programmer, because the C compiler needs to know about the types of the parameters and return value to correctly allocate them on the stack.


2 Answers

The function has to be declared before it's getting called. This could be done in various ways:

  • Write down the prototype in a header
    Use this if the function shall be callable from several source files. Just write your prototype
    int Fibonacci(int number);
    down in a .h file (e.g. myfunctions.h) and then #include "myfunctions.h" in the C code.

  • Move the function before it's getting called the first time
    This means, write down the function
    int Fibonacci(int number){..}
    before your main() function

  • Explicitly declare the function before it's getting called the first time
    This is the combination of the above flavors: type the prototype of the function in the C file before your main() function

As an additional note: if the function int Fibonacci(int number) shall only be used in the file where it's implemented, it shall be declared static, so that it's only visible in that translation unit.

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eckes Avatar answered Sep 30 '22 08:09

eckes


The compiler wants to know the function before it can use it

just declare the function before you call it

#include <stdio.h>  int Fibonacci(int number); //now the compiler knows, what the signature looks like. this is all it needs for now  int main(int argc, const char * argv[]) {     int input;     printf("Please give me a number : ");     scanf("%d", &input);     getchar();     printf("The fibonacci number of %d is : %d", input, Fibonacci(input)); //!!!  }/* main */  int Fibonacci(int number) { //… 
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vikingosegundo Avatar answered Sep 30 '22 06:09

vikingosegundo