I remember that since the beginning of times the most popular approach to implementing std::list<>::sort()
was the classic Merge Sort algorithm implemented in bottom-up fashion (see also What makes the gcc std::list sort implementation so fast?).
I remember seeing someone aptly refer to this strategy as "onion chaining" approach.
At least that's the way it is in GCC's implementation of C++ standard library (see, for example, here). And this is how it was in old Dimkumware's STL in MSVC version of standard library, as well as in all versions of MSVC all the way to VS2013.
However, the standard library supplied with VS2015 suddenly no longer follows this sorting strategy. The library shipped with VS2015 uses a rather straightforward recursive implementation of top-down Merge Sort. This strikes me as strange, since top-down approach requires access to the mid-point of the list in order to split it in half. Since std::list<>
does not support random access, the only way to find that mid-point is to literally iterate through half of the list. Also, at the very beginning it is necessary to know the total number of elements in the list (which was not necessarily an O(1) operation before C++11).
Nevertheless, std::list<>::sort()
in VS2015 does exactly that. Here's an excerpt from that implementation that locates the mid-point and performs recursive calls
... iterator _Mid = _STD next(_First, _Size / 2); _First = _Sort(_First, _Mid, _Pred, _Size / 2); _Mid = _Sort(_Mid, _Last, _Pred, _Size - _Size / 2); ...
As you can see, they just nonchalantly use std::next
to walk through the first half of the list and arrive at _Mid
iterator.
What could be the reason behind this switch, I wonder? All I see is a seemingly obvious inefficiency of repetitive calls to std::next
at each level of recursion. Naive logic says that this is slower. If they are willing to pay this kind of price, they probably expect to get something in return. What are they getting then? I don't immediately see this algorithm as having better cache behavior (compared to the original bottom-up approach). I don't immediately see it as behaving better on pre-sorted sequences.
Granted, since C++11 std::list<>
is basically required to store its element count, which makes the above slightly more efficient, since we always know the element count in advance. But that still does not seem to be enough to justify the sequential scan on each level of recursion.
(Admittedly, I haven't tried to race the implementations against each other. Maybe there are some surprises there.)
Yes, std::list<>::sort is guaranteed to be stable.
std::list , being a linked list, cannot provide random access to its elements efficiently. That's why it provides its own specialized sort algorithm.
std::sort() is a built-in function in C++'s Standard Template Library. The function takes in a beginning iterator, an ending iterator, and (by default) sorts the iterable in ascending order. The function can also be used for custom sorting by passing in a comparator function that returns a boolean.
In general, std::sort is indeed faster than qsort because of a couple of these things: qsort operates on void* , which first requires a dereference, and second requires the size of the data type to perform the swaps.
Note this answer has been updated to address all of the issues mentioned in the comments below and after the question, by making the same change from an array of lists to an array of iterators, while retaining the faster bottom up merge sort algorithm, and eliminating the small chance of stack overflow due to recursion with the top down merge sort algorithm.
The reason I didn't originally consider iterators was due to the VS2015 change to top down, leading me to believe there was some issue with trying to change the existing bottom up algorithm to use iterators, requiring a switch to the slower top down algorithm. It was only when I tried to analyze the switch to iterators myself that I realized there was a solution for bottom up algorithm.
In @sbi's comment, he asked the author of the top down approach, Stephan T. Lavavej, why the change was made. Stephan's response was "to avoid memory allocation and default constructing allocators". VS2015 introduced non-default-constructible and stateful allocators, which presents an issue when using the prior version's array of lists, as each instance of a list allocates a dummy node, and a change would be needed to handle no default allocator.
Lavavej's solution was to switch to using iterators to keep track of run boundaries within the original list instead of an internal array of lists. The merge logic was changed to use 3 iterator parameters, 1st parameter is iterator to start of left run, 2nd parameter is iterator to end of left run == iterator to start of right run, 3rd parameter is iterator to end of right run. The merge process uses std::list::splice to move nodes within the original list during merge operations. This has the added benefit of being exception safe. If a caller's compare function throws an exception, the list will be re-ordered, but no loss of data will occur (assuming splice can't fail). With the prior scheme, some (or most) of the data would be in the internal array of lists if an exception occurred, and data would be lost from the original list.
However the switch to top down merge sort was not needed. Initially, thinking there was some unknown to me reason for VS2015 switch to top down, I focused on using the internal interfaces in the same manner as std::list::splice. I later decided to investigate switching bottom up to use an array of iterators. I realized the order of runs stored in the internal array was newest (array[0] = rightmost) to oldest (array[last] = leftmost), and that it could use the same iterator based merge logic as VS2015's top down approach.
For bottom up merge sort, array[i] is an iterator to the start of a sorted sub-list with 2^i nodes, or it is empty (using std::list::end to indicate empty). The end of each sorted sub-list will be the start of a sorted sub-list in the next prior non-empty entry in the array, or if at the start of the array, in a local iterator (it points to end of newest run). Similar to the top down approach, the array of iterators is only used to keep track of sorted run boundaries within the original linked list, while the merge process uses std::list::splice to move nodes within the original linked list.
If a linked list is large and the nodes scattered, there will be a lot of cache misses. Bottom up will be about 30% faster than top down (equivalent to stating top down is about 42% slower than bottom up ). Then again, if there's enough memory, it would usually be faster to move the list to an array or vector, sort the array or vector, then create a new list from the sorted array or vector.
Example C++ code:
#define ASZ 32 template <typename T> void SortList(std::list<T> &ll) { if (ll.size() < 2) // return if nothing to do return; std::list<T>::iterator ai[ASZ]; // array of iterators std::list<T>::iterator mi; // middle iterator (end lft, bgn rgt) std::list<T>::iterator ei; // end iterator size_t i; for (i = 0; i < ASZ; i++) // "clear" array ai[i] = ll.end(); // merge nodes into array for (ei = ll.begin(); ei != ll.end();) { mi = ei++; for (i = 0; (i < ASZ) && ai[i] != ll.end(); i++) { mi = Merge(ll, ai[i], mi, ei); ai[i] = ll.end(); } if(i == ASZ) i--; ai[i] = mi; } // merge array into single list ei = ll.end(); for(i = 0; (i < ASZ) && ai[i] == ei; i++); mi = ai[i++]; while(1){ for( ; (i < ASZ) && ai[i] == ei; i++); if (i == ASZ) break; mi = Merge(ll, ai[i++], mi, ei); } } template <typename T> typename std::list<T>::iterator Merge(std::list<T> &ll, typename std::list<T>::iterator li, typename std::list<T>::iterator mi, typename std::list<T>::iterator ei) { std::list<T>::iterator ni; (*mi < *li) ? ni = mi : ni = li; while(1){ if(*mi < *li){ ll.splice(li, ll, mi++); if(mi == ei) return ni; } else { if(++li == mi) return ni; } } }
Example replacement code for VS2019's std::list::sort() (the merge logic was made into a separate internal function, since it's now used in two places).
private: template <class _Pr2> iterator _Merge(_Pr2 _Pred, iterator _First, iterator _Mid, iterator _Last){ iterator _Newfirst = _First; for (bool _Initial_loop = true;; _Initial_loop = false) { // [_First, _Mid) and [_Mid, _Last) are sorted and non-empty if (_DEBUG_LT_PRED(_Pred, *_Mid, *_First)) { // consume _Mid if (_Initial_loop) { _Newfirst = _Mid; // update return value } splice(_First, *this, _Mid++); if (_Mid == _Last) { return _Newfirst; // exhausted [_Mid, _Last); done } } else { // consume _First ++_First; if (_First == _Mid) { return _Newfirst; // exhausted [_First, _Mid); done } } } } template <class _Pr2> void _Sort(iterator _First, iterator _Last, _Pr2 _Pred, size_type _Size) { // order [_First, _Last), using _Pred, return new first // _Size must be distance from _First to _Last if (_Size < 2) { return; // nothing to do } const size_t _ASZ = 32; // array size iterator _Ai[_ASZ]; // array of iterators to runs iterator _Mi; // middle iterator iterator _Li; // last (end) iterator size_t _I; // index to _Ai for (_I = 0; _I < _ASZ; _I++) // "empty" array _Ai[_I] = _Last; // _Ai[] == _Last => empty entry // merge nodes into array for (_Li = _First; _Li != _Last;) { _Mi = _Li++; for (_I = 0; (_I < _ASZ) && _Ai[_I] != _Last; _I++) { _Mi = _Merge(_Pass_fn(_Pred), _Ai[_I], _Mi, _Li); _Ai[_I] = _Last; } if (_I == _ASZ) _I--; _Ai[_I] = _Mi; } // merge array runs into single run for (_I = 0; _I < _ASZ && _Ai[_I] == _Last; _I++); _Mi = _Ai[_I++]; while (1) { for (; _I < _ASZ && _Ai[_I] == _Last; _I++); if (_I == _ASZ) break; _Mi = _Merge(_Pass_fn(_Pred), _Ai[_I++], _Mi, _Last); } }
The remainder of this answer is historical.
I was able to reproduce the issue (old sort fails to compile, new one works) based on a demo from @IgorTandetnik:
#include <iostream> #include <list> #include <memory> template <typename T> class MyAlloc : public std::allocator<T> { public: MyAlloc(T) {} // suppress default constructor template <typename U> MyAlloc(const MyAlloc<U>& other) : std::allocator<T>(other) {} template< class U > struct rebind { typedef MyAlloc<U> other; }; }; int main() { std::list<int, MyAlloc<int>> l(MyAlloc<int>(0)); l.push_back(3); l.push_back(0); l.push_back(2); l.push_back(1); l.sort(); return 0; }
I noticed this change back in July, 2016 and emailed P.J. Plauger about this change on August 1, 2016. A snippet of his reply:
Interestingly enough, our change log doesn't reflect this change. That probably means it was "suggested" by one of our larger customers and got by me on the code review. All I know now is that the change came in around the autumn of 2015. When I reviewed the code, the first thing that struck me was the line:
iterator _Mid = _STD next(_First, _Size / 2);
which, of course, can take a very long time for a large list.
The code looks a bit more elegant than what I wrote in early 1995(!), but definitely has worse time complexity. That version was modeled after the approach by Stepanov, Lee, and Musser in the original STL. They are seldom found to be wrong in their choice of algorithms.
I'm now reverting to our latest known good version of the original code.
I don't know if P.J. Plauger's reversion to the original code dealt with the new allocator issue, or if or how Microsoft interacts with Dinkumware.
For a comparison of the top down versus bottom up methods, I created a linked list with 4 million elements, each consisting of one 64 bit unsigned integer, assuming I would end up with a doubly linked list of nearly sequentially ordered nodes (even though they would be dynamically allocated), filled them with random numbers, then sorted them. The nodes don't move, only the linkage is changed, but now traversing the list accesses the nodes in random order. I then filled those randomly ordered nodes with another set of random numbers and sorted them again. I compared the 2015 top down approach with the prior bottom up approach modified to match the other changes made for 2015 (sort() now calls sort() with a predicate compare function, rather than having two separate functions). These are the results. update - I added a node pointer based version and also noted the time for simply creating a vector from list, sorting vector, copy back.
sequential nodes: 2015 version 1.6 seconds, prior version 1.5 seconds random nodes: 2015 version 4.0 seconds, prior version 2.8 seconds random nodes: node pointer based version 2.6 seconds random nodes: create vector from list, sort, copy back 1.25 seconds
For sequential nodes, the prior version is only a bit faster, but for random nodes, the prior version is 30% faster, and the node pointer version 35% faster, and creating a vector from the list, sorting the vector, then copying back is 69% faster.
Below is the first replacement code for std::list::sort() I used to compare the prior bottom up with small array (_BinList[]) method versus VS2015's top down approach I wanted the comparison to be fair, so I modified a copy of < list >.
void sort() { // order sequence, using operator< sort(less<>()); } template<class _Pr2> void sort(_Pr2 _Pred) { // order sequence, using _Pred if (2 > this->_Mysize()) return; const size_t _MAXBINS = 25; _Myt _Templist, _Binlist[_MAXBINS]; while (!empty()) { // _Templist = next element _Templist._Splice_same(_Templist.begin(), *this, begin(), ++begin(), 1); // merge with array of ever larger bins size_t _Bin; for (_Bin = 0; _Bin < _MAXBINS && !_Binlist[_Bin].empty(); ++_Bin) _Templist.merge(_Binlist[_Bin], _Pred); // don't go past end of array if (_Bin == _MAXBINS) _Bin--; // update bin with merged list, empty _Templist _Binlist[_Bin].swap(_Templist); } // merge bins back into caller's list for (size_t _Bin = 0; _Bin < _MAXBINS; _Bin++) if(!_Binlist[_Bin].empty()) this->merge(_Binlist[_Bin], _Pred); }
I made some minor changes. The original code kept track of the actual maximum bin in a variable named _Maxbin, but the overhead in the final merge is small enough that I removed the code associated with _Maxbin. During the array build, the original code's inner loop merged into a _Binlist[] element, followed by a swap into _Templist, which seemed pointless. I changed the inner loop to just merge into _Templist, only swapping once an empty _Binlist[] element is found.
Below is a node pointer based replacement for std::list::sort() I used for yet another comparison. This eliminates allocation related issues. If a compare exception is possible and occurred, all the nodes in the array and temp list (pNode) would have to be appended back to the original list, or possibly a compare exception could be treated as a less than compare.
void sort() { // order sequence, using operator< sort(less<>()); } template<class _Pr2> void sort(_Pr2 _Pred) { // order sequence, using _Pred const size_t _NUMBINS = 25; _Nodeptr aList[_NUMBINS]; // array of lists _Nodeptr pNode; _Nodeptr pNext; _Nodeptr pPrev; if (this->size() < 2) // return if nothing to do return; this->_Myhead()->_Prev->_Next = 0; // set last node ->_Next = 0 pNode = this->_Myhead()->_Next; // set ptr to start of list size_t i; for (i = 0; i < _NUMBINS; i++) // zero array aList[i] = 0; while (pNode != 0) // merge nodes into array { pNext = pNode->_Next; pNode->_Next = 0; for (i = 0; (i < _NUMBINS) && (aList[i] != 0); i++) { pNode = _MergeN(_Pred, aList[i], pNode); aList[i] = 0; } if (i == _NUMBINS) i--; aList[i] = pNode; pNode = pNext; } pNode = 0; // merge array into one list for (i = 0; i < _NUMBINS; i++) pNode = _MergeN(_Pred, aList[i], pNode); this->_Myhead()->_Next = pNode; // update sentinel node links pPrev = this->_Myhead(); // and _Prev pointers while (pNode) { pNode->_Prev = pPrev; pPrev = pNode; pNode = pNode->_Next; } pPrev->_Next = this->_Myhead(); this->_Myhead()->_Prev = pPrev; } template<class _Pr2> _Nodeptr _MergeN(_Pr2 &_Pred, _Nodeptr pSrc1, _Nodeptr pSrc2) { _Nodeptr pDst = 0; // destination head ptr _Nodeptr *ppDst = &pDst; // ptr to head or prev->_Next if (pSrc1 == 0) return pSrc2; if (pSrc2 == 0) return pSrc1; while (1) { if (_DEBUG_LT_PRED(_Pred, pSrc2->_Myval, pSrc1->_Myval)) { *ppDst = pSrc2; pSrc2 = *(ppDst = &pSrc2->_Next); if (pSrc2 == 0) { *ppDst = pSrc1; break; } } else { *ppDst = pSrc1; pSrc1 = *(ppDst = &pSrc1->_Next); if (pSrc1 == 0) { *ppDst = pSrc2; break; } } } return pDst; }
@sbi asked Stephan T. Lavavej, MSVC's standard library maintainer, who responded:
I did that to avoid memory allocation and default constructing allocators.
To this I'll add "free basic exception safety".
To elaborate: the pre-VS2015 implementation suffers from several defects:
_Myt _Templist, _Binlist[_MAXBINS];
creates a bunch of intermediate list
s (_Myt
is simply a typedef for the current instantiation of list
; a less confusing spelling for that is, well, list
) to hold the nodes during sorting, but these list
s are default constructed, which leads to a multitude of problems: list
will attempt to default construct its allocator.this->get_allocator()
, which means that the later splice
s and merge
s are technically undefined behavior and may well break in debug builds. ("Technically", because the nodes are all merged back in the end, so you don't actually deallocate with the wrong allocator if the function successfully completes.)list
uses a dynamically allocated sentinel node, which means that the above will perform _MAXBINS + 1
dynamic allocations. I doubt that many people expect sort
to potentially throw bad_alloc
. If the allocator is stateful, then these sentinel nodes may not be even allocated from the right place (see #2).list
s, those elements are simply destroyed with the list
s during stack unwinding. Users of sort
don't expect the list to be sorted if sort
throws an exception, of course, but they probably also don't expect the elements to go missing. list
s will be deallocating and destroying the nodes spliced into them with the wrong allocator.Are those defects fixable? Probably. #1 and #2 can be fixed by passing get_allocator()
to the constructor of the list
s:
_Myt _Templist(get_allocator()); _Myt _Binlist[_MAXBINS] = { _Myt(get_allocator()), _Myt(get_allocator()), _Myt(get_allocator()), /* ... repeat _MAXBINS times */ };
The exception safety problem can be fixed by surrounding the loop with a try-catch
that splices all the nodes in the intermediate list
s back into *this
without regard to order if an exception is thrown.
Fixing #3 is harder, because that means not using list
at all as the holder of nodes, which probably requires a decent amount of refactoring, but it's doable.
The question is: is it worth jumping through all these hoops to improve the performance of a container that has reduced performance by design? After all, someone who really cares about performance probably won't be using list
in the first place.
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