`static` keyword inside function?

Question

It makes the function remember the value of the given variable ($has_run in your example) between multiple calls.

You could use this for different purposes, for example:

function doStuff() {
  static $cache = null;

  if ($cache === null) {
     $cache = '%heavy database stuff or something%';
  }

  // code using $cache
}

In this example, the if would only be executed once. Even if multiple calls to doStuff would occur.

Seems like nobody mentioned so far, that static variables inside different instances of the same class remain their state. So be careful when writing OOP code.

Consider this:

class Foo
{
    public function call()
    {
        static $test = 0;

        $test++;
        echo $test . PHP_EOL; 
    }
}

$a = new Foo();
$a->call(); // 1
$a->call(); // 2
$a->call(); // 3


$b = new Foo();
$b->call(); // 4
$b->call(); // 5

If you want a static variable to remember its state only for current class instance, you'd better stick to a class property, like this:

class Bar
{
    private $test = 0;

    public function call()
    {
        $this->test++;
        echo $this->test . PHP_EOL; 
    }
}


$a = new Bar();
$a->call(); // 1
$a->call(); // 2
$a->call(); // 3


$b = new Bar();
$b->call(); // 1
$b->call(); // 2

Given the following example:

function a($s){
    static $v = 10;
    echo $v;
    $v = $s;
}

First call of

a(20);

will output 10, then $v to be 20. The variable $v is not garbage collected after the function ends, as it is a static (non-dynamic) variable. The variable will stay within its scope until the script totally ends.

Therefore, the following call of

a(15);

will then output 20, and then set $v to be 15.

Static works the same way as it does in a class. The variable is shared across all instances of a function. In your particular example, once the function is run, $has_run is set to TRUE. All future runs of the function will have $has_run = TRUE. This is particularly useful in recursive functions (as an alternative to passing the count).

A static variable exists only in a local function scope, but it does not lose its value when program execution leaves this scope.

See http://php.net/manual/en/language.variables.scope.php

To expand on the answer of Yang

If you extend a class with static variables, the individual extended classes will hold their "own" referenced static that's shared between instances.

<?php
class base {
     function calc() {
        static $foo = 0;
        $foo++;
        return $foo;
     }
}

class one extends base {
    function e() {
        echo "one:".$this->calc().PHP_EOL;
    }
}
class two extends base {
    function p() {
        echo "two:".$this->calc().PHP_EOL;
    }
}
$x = new one();
$y = new two();
$x_repeat = new one();

$x->e();
$y->p();
$x->e();
$x_repeat->e();
$x->e();
$x_repeat->e();
$y->p();

outputs:

one:1
two:1
one:2
one:3 <-- x_repeat
one:4
one:5 <-- x_repeat
two:2

http://ideone.com/W4W5Qv

static variable in a function means that no matter how many times you call the function, there's only 1 variable.

<?php

class Foo{
    protected static $test = 'Foo';
    function yourstatic(){
        static $test = 0;
        $test++;
        echo $test . "\n"; 
    }

    function bar(){
        $test = 0;
        $test++;
        echo $test . "\n";
    }
}

$f = new Foo();
$f->yourstatic(); // 1
$f->yourstatic(); // 2
$f->yourstatic(); // 3
$f->bar(); // 1
$f->bar(); // 1
$f->bar(); // 1

?>