SQLite insert or ignore and return original _rowid_

Question

I've spent some time reading the SQLite docs, various questions and answers here on Stack Overflow, and this thing, but have not come to a full answer.

I know that there is no way to do something like INSERT OR IGNORE INTO foo VALUES(...) with SQLite and get back the rowid of the original row, and that the closest to it would be INSERT OR REPLACE but that deletes the entire row and inserts a new row and thus gets a new rowid.

Example table:

CREATE TABLE foo(
    id INTEGER PRIMARY KEY AUTOINCREMENT,
    data TEXT
);

Right now I can do:

sql = sqlite3.connect(":memory:")
# create database
sql.execute("INSERT OR IGNORE INTO foo(data) VALUES(?);", ("Some text.", ))
the_id_of_the_row = None
for row in sql.execute("SELECT id FROM foo WHERE data = ?", ("Some text.", )):
    the_id_of_the_row = row[0]

But something ideal would look like:

the_id_of_the_row = sql.execute("INSERT OR IGNORE foo(data) VALUES(?)", ("Some text", )).lastrowid

What is the best (read: most efficient) way to insert a row into a table and return the rowid, or to ignore the row if it already exists and just get the rowid? Efficiency is important because this will be happening quite often.

Is there a way to INSERT OR IGNORE and return the rowid of the row that the ignored row was compared to? This would be great, as it would be just as efficient as an insert.

Answer 1

The way that worked the best for me was to insert or ignore the values, and the select the rowid in two separate steps. I used a unique constraint on the data column to both speed up selects and avoid duplicates.

sql.execute("INSERT OR IGNORE INTO foo(data) VALUES(?);" ("Some text.", ))
last_row_id = sql.execute("SELECT id FROM foo WHERE data = ?;" ("Some text. ", ))

The select statement isn't as slow as I thought it would be. This, it seems, is due to SQLite automatically creating an index for the unique columns.