Menu
This is my script
SELECT COUNT( [Id]) as [Count Of Register],
Tag as [Tag]
FROM [Members]
Group By Tag
Order By [Count Of Register] Desc;
Returned table is like this:
Count Tag
550 ----1
550 ----2
545 ----3
545 ----4
545 ----5
So, this time I need Count of Tag, Group by this new Count field.
Some Returned Values Like:
2 ---550
3 ---545
Is there any way without using new table or Template Table or any Storage Table just by query?
993
The GROUP BY statement is often used with aggregate functions ( COUNT() , MAX() , MIN() , SUM() , AVG() ) to group the result-set by one or more columns.
The use of COUNT() function in conjunction with GROUP BY is useful for characterizing our data under various groupings. A combination of same values (on a column) will be treated as an individual group.
Using COUNT, without GROUP BY clause will return a total count of a number of rows present in the table. Adding GROUP BY, we can COUNT total occurrences for each unique value present in the column. we can use the following command to create a database called geeks.
COUNT(*) returns the number of items in a group. This includes NULL values and duplicates. COUNT(ALL expression) evaluates expression for each row in a group, and returns the number of nonnull values.
SELECT [Count Of Register], COUNT(1) [Grouped Count]
FROM
(
SELECT COUNT( [Id]) as [Count Of Register],
Tag as [Tag]
FROM [Members]
Group By Tag
) MyTable
GROUP BY [Count Of Register]
You could use
SELECT [Count Of Register], COUNT(*) FROM
(SELECT COUNT([Id]) as [Count Of Register], Tag as [Tag]
FROM [Members] GROUP BY Tag) q
GROUP BY [Count Of Register]
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
