See the results of below queries:
>> SELECT ADD_MONTHS(TO_DATE('30-MAR-11','DD-MON-RR'),-4) FROM DUAL;
30-NOV-10
>> SELECT ADD_MONTHS(TO_DATE('30-NOV-10','DD-MON-RR'),4) FROM DUAL;
31-MAR-11
How can I get '30-MAR-11' when adding 4 months to some date?
Please help.
ADD_MONTHS returns the date date plus integer months. A month is defined by the session parameter NLS_CALENDAR . The date argument can be a datetime value or any value that can be implicitly converted to DATE . The integer argument can be an integer or any value that can be implicitly converted to an integer.
ADD_MONTHS() function returns a date with a given number of months added (date plus integer months).
The ADD_MONTHS function takes a DATETIME or DATE expression as its first argument, and requires a second integer argument, specifying the number of months to add to the first argument value. The second argument can be positive or negative.
LAST_DAY returns the date of the last day of the month that contains date . The return type is always DATE , regardless of the datatype of date . Examples. The following statement determines how many days are left in the current month.
There is another question here about Oracle and Java
It states that
From the Oracle reference on add_months http://download-west.oracle.com/docs/cd/B19306_01/server.102/b14200/functions004.htm
If date is the last day of the month or if the resulting month has fewer days than the day component of date, then the result is the last day of the resulting month. Otherwise, the result has the same day component as date.
So I guess you have to manually check stating day and ending day to change the behaviour of the function. Or maybe by adding days instead of months. (But I didn't find a add_day
function in the ref)
As a workaround, I might possibly use this algorithm:
TargetDate1
using ADD_MONTHS
.Alternatively calculate the target date TargetDate2
like this:
1) apply ADD_MONTHS
to the first of the source date's month;
2) add the difference of days between the source date and the beginning of the same month.
Select the LEAST
between the TargetDate1
and TargetDate2
.
So in the end, the target date will contain a different day component if the source date's day component is greater than the number of day in the target month. In this case the target date will be the last day of the corresponding month.
I'm not really sure about my knowledge of Oracle's SQL syntax, but basically the implementation might look like this:
SELECT
LEAST(
ADD_MONTHS(SourceDate, Months),
ADD_MONTHS(TRUNC(SourceDate, 'MONTH'), Months)
+ (SourceDate - TRUNC(SourceDate, 'MONTH'))
) AS TargetDate
FROM (
SELECT
TO_DATE('30-NOV-10', 'DD-MON-RR') AS SourceDate,
4 AS Months
FROM DUAL
)
Here is a detailed illustration of how the method works:
SourceDate = '30-NOV-10'
Months = 4
TargetDate1 = ADD_MONTHS('30-NOV-10', 4) = '31-MAR-11' /* unacceptable */
TargetDate2 = ADD_MONTHS('01-NOV-10', 4) + (30 - 1)
= '01-MAR-11' + 29 = '30-MAR-11' /* acceptable */
TargetDate = LEAST('31-MAR-11', '30-MAR-11') = '30-MAR-11'
And here are some more examples to show different cases:
SourceDate | Months | TargetDate1 | TargetDate2 | TargetDate
-----------+--------+-------------+-------------+-----------
29-NOV-10 | 4 | 29-MAR-11 | 29-MAR-11 | 29-MAR-11
30-MAR-11 | -4 | 30-NOV-10 | 30-NOV-10 | 30-NOV-10
31-MAR-11 | -4 | 30-NOV-10 | 01-DEC-10 | 30-NOV-10
30-NOV-10 | 3 | 28-FEB-11 | 02-MAR-11 | 28-FEB-11
You can use interval arithmetic to get the result you want
SQL> select date '2011-03-30' - interval '4' month
2 from dual;
DATE'2011
---------
30-NOV-10
SQL> ed
Wrote file afiedt.buf
1 select date '2010-11-30' + interval '4' month
2* from dual
SQL> /
DATE'2010
---------
30-MAR-11
Be aware, however, that there are pitfalls to interval arithmetic if you're working with days that don't exist in every month
SQL> ed
Wrote file afiedt.buf
1 select date '2011-03-31' + interval '1' month
2* from dual
SQL> /
select date '2011-03-31' + interval '1' month
*
ERROR at line 1:
ORA-01839: date not valid for month specified
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