I am using json-spray. It seems that when I attempt to print a parsed JsString value, it includes book-ended quotes on the string.
val x1 = """ {"key1": "value1", "key2": 4} """
println(x1.asJson)
println(x1.asJson.convertTo[Map[String, JsValue]])
Which outputs:
{"key1":"value1","key2":4}
Map(key1 -> "value1", key2 -> 4)
But that means that the string value of key1 is actually quoted since scala displays strings without their quotes. i.e. val k = "value1"
outputs: value1
not "value1"
. Perhaps I am doing something wrong, but the best I could come up with to alleviate this was the following:
val m = x1.asJson.convertTo[Map[String, JsValue]]
val z = m.map({
case(x,y) => {
val ny = y.toString( x => x match {
case v: JsString =>
v.toString().tail.init
case v =>
v.toString()
} )
(x,ny)
}})
println(z)
Which outputs a correctly displayed string:
Map(key1 -> value1, key2 -> 4)
But this solution won't work for recursively nested JSON. Is there a better workaround?
Try this:
import spray.json._
import DefaultJsonProtocol._
val jsString = new JsString("hello")
val string = jsString.convertTo[String]
In the new version, there is a little difference:
libraryDependencies ++= "io.spray" % "spray-json_2.12" % "1.3.3"
import spray.json.DefaultJsonProtocol._
import spray.json._
object SprayJson extends ExampleBase {
private def jsonValue(): Map[String, String] = {
val x1 = """ {"key1": "value1", "key2": 4} """
val json = x1.parseJson
println(json.prettyPrint)
json.convertTo[Map[String, JsValue]].map(v =>
(v._1, v._2 match {
case s: JsString => s.value
case o => o.toString()
}))
}
override def runAll(): Unit = {
println(jsonValue())
}
}
The output:
{
"key1": "value1",
"key2": 4
}
Map(key1 -> value1, key2 -> 4)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With