Suppose I have a NumPy
2D
array A
:
>>> import numpy as np
>>> A=np.arange(30).reshape(3,10)
>>> A
array([[ 0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
[20, 21, 22, 23, 24, 25, 26, 27, 28, 29]])
I need to get two arrays B
and C
with the following properties:
B = array([[ 0, 3, 4, 5, 6, 7, 8, 9],
[10, 13, 14, 15, 16, 17, 18, 19],
[20, 23, 24, 25, 26, 27, 28, 29]])
C = array([[ 1, 2],
[11, 12],
[21, 22]])
What is the easiest way to accomplish this?
Note that I have to get all sets of C
(2 adjacent columns) and B
(which is A
without C
). I tried different NumPy
constructs like np.delete
, np.hstack
but nothing seem to work at the corner conditions like in the above example.
One of the simplest ways is to use indexing to select the appropriate columns:
>>> A[:, [1, 2]] # choose all rows from columns 1-2 (gives C)
array([[ 1, 2],
[11, 12],
[21, 22]])
>>> A[:, np.r_[0, 3:10]] # choose all rows from columns 0, 3-9 (gives B)
array([[ 0, 3, 4, 5, 6, 7, 8, 9],
[10, 13, 14, 15, 16, 17, 18, 19],
[20, 23, 24, 25, 26, 27, 28, 29]])
Alternatively, you could try hsplit
break up A
and then concatenate bits back together. This feels less efficient than the indexing method above though:
>>> splits = np.hsplit(A, [1, 3])
>>> B = np.hstack((splits[0], splits[2]))
>>> C = splits[1]
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With