split xml value with xpath and check string position

Question

I have the following xml file:

 <courses>
   <course>
    <name>Course 1</name>
    <code>00162</code>
    <questions>2,2,1,1,2,1,1,1</questions>
   </course>
   </courses>

I need to query the file (I'm using xpath) to split the 'questions' element, check the position in which each number appears and check if it is number 1 or 2.

Basically I need to this in xpath:

Dim ints As String() = QuestionsString.ToString.Split(",")
Dim i As Integer

        For i = 0 To UBound(ints)    
            If ints(i) = "2" Then
             'do something
            Else
            'do something else
            End If
        Next

Update from comments

Hi, thank you. I was going to edit the question as it was incorrect. I want to get, for example, all course names and codes whose 'questions' element (after split) has "2" in the second position, as in 1,2,2,1,1,1,2,1 Thanks!

Answer 1

In XSLT 1.0, you would use a recursive template to split the string.

Borrowing from @Tomalak's answer to a similar question, is an example:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:template match="/">
    <!--Call the recursive template to split the string-->
        <xsl:call-template name="split">
            <xsl:with-param name="list" select="/courses/course/questions" />
        </xsl:call-template>
    </xsl:template>

    <xsl:template name="split">
        <xsl:param name="list"      select="''" />
        <xsl:param name="separator" select="','" />
        <xsl:if test="not($list = '' or $separator = '')">
            <xsl:variable name="head" select="substring-before(concat($list, $separator), $separator)" />
            <xsl:variable name="tail" select="substring-after($list, $separator)" />

            <!--Use the parsed value to do something-->
            <xsl:call-template name="handleQuestion">
                <xsl:with-param name="value" select="$head"/>
            </xsl:call-template>

            <xsl:call-template name="split">
                <xsl:with-param name="list"      select="$tail" />
                <xsl:with-param name="separator" select="$separator" />
            </xsl:call-template>
        </xsl:if>
    </xsl:template>

    <xsl:template name="handleQuestion">
        <xsl:param name="value" />
        <xsl:choose>
            <xsl:when test="$value=2">
                <!--Do something-->
            </xsl:when>
            <xsl:otherwise>
                <!--Do something else-->
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>
</xsl:stylesheet>

In XSLT 2.0, you can use the tokenize() function:

<?xml version="1.0"?>
<xsl:stylesheet version="2.0"
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:fn="http://www.w3.org/2005/xpath-functions"
    xmlns:xs="http://www.w3.org/2001/XMLSchema">
    <xsl:template match="/">
        <xsl:for-each select="tokenize(/courses/course/questions,',')">
            <xsl:choose>
                <xsl:when test="number(.)=2">
                    <!--Do something-->
                </xsl:when>
                <xsl:otherwise>
                    <!--Do something else-->
                </xsl:otherwise>
            </xsl:choose>
        </xsl:for-each>
    </xsl:template>
</xsl:stylesheet>