Split Strings in java by words

Question

How can I split the following word in to an array

That's the code

into

array
0 That
1 s
2 the
3 code

I tried something like this

String str = "That's the code";

        String[] strs = str.split("\\'");
        for (String sstr : strs) {
            System.out.println(sstr);
        }

But the output is

That
s the code

Answer 1

To specifically split on white space and the apostrophe:

public class Split {
    public static void main(String[] args) {
        String [] tokens = "That's the code".split("[\\s']");
        for(String s:tokens){
            System.out.println(s);
        }
    }
}

or to split on any non word character:

public class Split {
    public static void main(String[] args) {
        String [] tokens = "That's the code".split("[\\W]");
        for(String s:tokens){
            System.out.println(s);
        }
    }
}

Answer 2

The best solution I've found to split by words if your string contains accentuated letters is :

String[] listeMots = phrase.split("\\P{L}+");

For instance, if your String is

String phrase = "Salut mon homme, comment ça va aujourd'hui? Ce sera Noël puis Pâques bientôt.";

Then you will get the following words (enclosed within quotes and comma separated for clarity) :

"Salut", "mon", "homme", "comment", "ça", "va", "aujourd", "hui", "Ce", 
"sera", "Noël", "puis", "Pâques", "bientôt".

Hope this helps!

Answer 3

You can split according to non-characters chars:

String str = "That's the code";
String[] splitted = str.split("[\\W]");

For your input, output will be:

That
s
the
code