Based on the question posed by @Chips Ahoy, I decided to create a UDF to find the PercentRank of visible cells in a range.
While @Chips seems happy with my syntax correction, I am actually unable to get my UDF to work correctly.
When I run the below, the two addresses output read identical. In my example using a formula of =VisiblePercentRank($A$2:$A$41,0.5)
, both addresses output to the immediate window read $A$2:$A$41
, despite rows 3 to 11 being hidden by an autofilter.
Code:
Function VisiblePercentRank(x As Range, RankVal As Double)
Debug.Print x.Address, x.Rows.SpecialCells(xlCellTypeVisible).Address
VisiblePercentRank = WorksheetFunction.PercentRank(x.Rows.SpecialCells(xlCellTypeVisible), RankVal)
End Function
Also tried removing .Rows
:
Function VisiblePercentRank(x As Range, RankVal As Double)
Debug.Print x.Address, x.SpecialCells(xlCellTypeVisible).Address
VisiblePercentRank = WorksheetFunction.PercentRank(x.SpecialCells(xlCellTypeVisible), RankVal)
End Function
Should the second output not read $A$2,$A$12:$A$41
or have I missed something?
Using Excel/Office 2013, 64bit on Win7, 64bit.
BRAIN FRYING UPDATE
I have found that my UDF works if I run it from the immediate window:
?VisiblePercentRank(range("A2:A41"),0.5)
$A$2:$A$41 $A$2:$A$11,$A$39:$A$41
0.207
But if run from an in-cell formula of =VisiblePercentRank(A2:A41,0.5)
:
$A$2:$A$41 $A$2:$A$41
It seems that SpecialCells
is known to fail in UDFs. A few sources: 1, 2, 3
You'd have to create your own function. Perhaps something like this:
Function VisiblePercentRank(x As Range, RankVal As Double)
Debug.Print x.Address, VisibleCells(x).Address
VisiblePercentRank = WorksheetFunction.PercentRank(VisibleCells(x), RankVal)
End Function
Private Function VisibleCells(rng As Range) As Range
Dim r As Range
For Each r In rng
If r.EntireRow.Hidden = False Then
If VisibleCells Is Nothing Then
Set VisibleCells = r
Else
Set VisibleCells = Union(VisibleCells, r)
End If
End If
Next r
End Function
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