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Spawning process with arguments in node.js

I need to spawn a child process from node.js, whilst using ulimit to keep it from using to much memory.

Following the docs, it wasn't hard to get the basic spawn working: child = spawn("coffee", ["app.coffee"]).

However, doing what I do below just makes the spawn die silently.

child = spawn("ulimit", ["-m 65536;", "coffee app.coffee"])

If I would run ulimit -m 65536; coffee app.coffee - it works as intented.

What am I doing wrong here?

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Industrial Avatar asked Oct 08 '12 09:10

Industrial


Video Answer


1 Answers

Those are two different commands. Don't club them if you are using spawn. Use separate child processes.

 child1 = spawn('ulimit', ['-m', '65536']);  child2 = spawn('coffee', ['app.coffee']); 

If you are not interested in output stream(if you want just buffered output) you can use exec.

var exec = require('child_process').exec, child;  child = exec('ulimit -m 65536; coffee app.coffee',   function (error, stdout, stderr) {     console.log('stdout: ' + stdout);   } }); 
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vinayr Avatar answered Nov 03 '22 23:11

vinayr