I'm trying to write a script to allow me to log in to a console servers 48 ports so that I can quickly determine what devices are connected to each serial line.
Essentially I want to be able to have a script that, given a list of hosts/ports, telnets to the first device in the list and leaves me in interactive mode so that I can log in and confirm the device, then when I close the telnet session, connects to the next session in the list.
The problem I'm facing is that if I start a telnet session from within an executable bash script, the session terminates immediately, rather than waiting for input.
For example, given the following code:
$ cat ./telnetTest.sh
#!/bin/bash
while read line
do
telnet $line
done
$
When I run the command 'echo "hostname" | testscript.sh' I receive the following output:
$ echo "testhost" | ./telnetTest.sh
Trying 192.168.1.1...
Connected to testhost (192.168.1.1).
Escape character is '^]'.
Connection closed by foreign host.
$
Does anyone know of a way to stop the telnet session being closed automatically?
You need to redirect the Terminal input to the telnet
process. This should be /dev/tty
. So your script will look something like:
#!/bin/bash
for HOST in `cat`
do
echo Connecting to $HOST...
telnet $HOST </dev/tty
done
I think you should look at expect program. It`s present in all modern linux distros. Here is some exmaple script:
#!/usr/bin/expect -f
spawn telnet $host_name
expect {
"T0>" {}
-re "Connection refused|No route to host|Invalid argument|lookup failure"
{send_user "\r******* connection error, bye.\n";exit}
default {send_user "\r******* connection error (telnet timeout),
bye.\n";exit}
}
send "command\n"
expect -timeout 1 "something"
spawn command start remote login program (telnet, ssh, netcat etc)
expext command used to... hm.. expect something from remote session
send - sending commands
send_user - to print comments to stdout
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