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Is it possible in python to sort a list of words not according to the english alphabet but according to a self created alphabet.
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In Python, there are two ways, sort() and sorted() , to sort lists ( list ) in ascending or descending order. If you want to sort strings ( str ) or tuples ( tuple ), use sorted() .
Use the Python List sort() method to sort a list in place. The sort() method sorts the string elements in alphabetical order and sorts the numeric elements from smallest to largest. Use the sort(reverse=True) to reverse the default sort order.
Python sorted() Function The sorted() function returns a sorted list of the specified iterable object. You can specify ascending or descending order. Strings are sorted alphabetically, and numbers are sorted numerically.
You can normally define custom comparison methods so the sort is performed within your restrictions. I've never coded a line of Python in my life, but it's similar enough to Ruby for me to notice that the following excerpt from this page might help you:
alphabet = "zyxwvutsrqpomnlkjihgfedcba"
inputWords = ["england", "france", "spain", "italy", "greece", "portugal",
"canada", "usa", "mexico", "peru", "cuba", "chile", "argentina",
"zimbabwe", "uganda", "congo", "zambia", "namibia", "ghana"]
print sorted(inputWords, key=lambda word: [alphabet.index(c) for c in word])
You might also want to check out these articles. Good luck!
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