I have a cherrypy app that I'm controlling over http with a wxpython ui. I want to kill the server when the ui closes, but I don't know how to do that. Right now I'm just doing a sys.exit() on the window close event but thats resulting in
Traceback (most recent call last):
File "ui.py", line 67, in exitevent
urllib.urlopen("http://"+server+"/?sigkill=1")
File "c:\python26\lib\urllib.py", line 87, in urlopen
return opener.open(url)
File "c:\python26\lib\urllib.py", line 206, in open
return getattr(self, name)(url)
File "c:\python26\lib\urllib.py", line 354, in open_http
'got a bad status line', None)
IOError: ('http protocol error', 0, 'got a bad status line', None)
is that because I'm not stopping cherrypy properly?
exit : >>> help(cherrypy. engine. exit) exit(self) method of cherrypy.
CherryPy comes with its own web (HTTP) server. That is why CherryPy is self-contained and allows users to run a CherryPy application within minutes of getting the library. The web server acts as the gateway to the application with the help of which all the requests and responses are kept in track.
CherryPy is an object-oriented web application framework using the Python programming language. It is designed for rapid development of web applications by wrapping the HTTP protocol but stays at a low level and does not offer much more than what is defined in RFC 7231.
How are you stopping CherryPy? By sending a SIGKILL to itself? You should send TERM instead at the least, but even better would be to call cherrypy.engine.exit()
(version 3.1+). Both techniques will allow CherryPy to shut down more gracefully, which includes allowing any in-process requests (like your "?sigkill=1" request itself) to finish up and close cleanly.
I use os._exit. I also put it on a thread, so that I can serve up a "you've quit the server" page before exiting.
class MyApp(object):
@cherrypy.expose
def exit(self):
"""
/exit
Quits the application
"""
threading.Timer(1, lambda: os._exit(0)).start()
return render("exit.html", {})
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