http://jsfiddle.net/9sKwJ/66/
tr.spacer { height: 40px; }
$.tablesorter.addWidget({
id: 'spacer',
format: function(table) {
var c = table.config,
$t = $(table),
$r = $t.find('tbody').find('tr'),
i, l, last, col, rows, spacers = [];
if (c.sortList && c.sortList[0]) {
$t.find('tr.spacer').removeClass('spacer');
col = c.sortList[0][0]; // first sorted column
rows = table.config.cache.normalized;
last = rows[0][col]; // text from first row
l = rows.length;
for (i=0; i < l; i++) {
// if text from row doesn't match last row,
// save it to add a spacer
if (rows[i][col] !== last) {
spacers.push(i-1);
last = rows[i][col];
}
}
// add spacer class to the appropriate rows
for (i=0; i<spacers.length; i++){
$r.eq(spacers[i]).addClass('spacer');
}
}
}
});
$('table').tablesorter({
widgets : ['spacer']
});
<table id="test">
<thead>
<tr>
<th>Name</th>
<th>Number</th>
<th>Another Example</th>
</tr>
</thead>
<tbody>
<tr>
<td>Test4</td>
<td>4</td>
<td>Hello4</td>
</tr>
<tr>
<td colspan="3">Test4</td>
</tr>
<tr>
<td>Test3</td>
<td>3</td>
<td>Hello3</td>
</tr>
<tr>
<td colspan="3">Test3</td>
</tr>
<tr>
<td>Test2</td>
<td>2</td>
<td>Hello2</td>
</tr>
<tr>
<td colspan="3">Test2</td>
</tr>
<tr>
<td>Test1</td>
<td>1</td>
<td>Hello1</td>
</tr>
<tr>
<td colspan="3">Test1</td>
</tr>
</tbody>
</table>
This sorts just the way I want it if you sort it by the first column, but the other two columns don't maintain the same paired 'tr' sort im looking for.
Any help on this?
Use the expand-child
class name on each duplicated row:
<tr>
<td>Test3</td>
<td>3</td>
<td>Hello3</td>
</tr>
<tr class="expand-child">
<td colspan="3">Test3</td>
</tr>
It's defined by the cssChildRow
option:
$('table').tablesorter({
cssChildRow: "expand-child"
});
Here is a demo of it in action.
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