Sorting bash arguments alphabetically

Question

How can I take sort bash arguments alphabetically?

$ ./script.sh bbb aaa ddd ccc

and put it into an array such that I now have an array {aaa, bbb, ccc, ddd}

Answer 1

You can do:

A=( $(sort <(printf "%s\n" "$@")) )

printf "%s\n" "${A[@]}"
aaa
bbb
ccc
ddd

It is using steps:

1. sort the arguments list i.e."$@"`
2. store output of sort in an array
3. Print the sorted array