I am writing a phonebook program in java and i need to list people in the list alphabetically and to do that i need to write a sorting algorithm for a list in java and it should use only compareTo() method. So can anyone help me to do that?
public void listAlpha()
{
Node tempNode = head;
for(int i = 0; i <= size; i++)
{
for(int j = 0; j <= i; j++)
{
int comparison = ((tempNode.getNext().getElement().getName()).compareTo(tempNode.getElement().getName()));
if(comparison < 0)
{
Person tempPerson = tempNode.getElement();
tempNode.setElement(tempNode.getNext().getElement());
tempNode.getNext().setElement(tempPerson);
tempNode = tempNode.getNext();
}
}
}
(By the way this is a homework and i am using my own data structures.)
This is the class that method i wrote above belongs:
import java.util.*;
/** Singly linked list implementation .*/
public class SLinkedList<E> implements LinkedList<E>, Iterable<E> {
protected Node<E> head; // head node of the list
protected Node<E> tail; // tail node of the list
protected int size; // number of nodes in the list
public Iterator<E> iterator()
{
return new LinkedListIterator(head);
}
/** Default constructor that creates an empty list */
public SLinkedList() {
head = null;
tail = null;
size = 0;
}
public int size() {
return size;
}
public boolean isEmpty() {
return size == 0;
}
public void addFirst(E newElement) {
Node<E> newNode = new Node(newElement,null);
if(size == 0) //if list is empty
tail = newNode;
newNode.setNext(head);
head = newNode;
size++;
}
public void addLast(E newElement) {
Node<E> newNode = new Node(newElement,null);
if(size == 0) //if list is empty
head = newNode;
if (size != 0) //if list is not empty
tail.setNext(newNode);
tail = newNode;
size++;
}
public E removeFirst() {
Node<E> tempNode = null;
if (size != 0) {
if(size == 1)
tail = null;
tempNode = head;
head = head.getNext();
tempNode.setNext(null);
size--;
}
//if list is empty then return null
return tempNode.getElement();
}
public E removeLast() {
Node<E> tempNode = head;
if(size == 0)
return null;
if(size == 1) {
head = null;
tail = null;
size--;
return tempNode.getElement();
}
//size is greater than 1
for(int i=1; i<=size-2; i++) {
tempNode = tempNode.getNext(); //go to element that before the tail
}
Node<E> tempNode2 = tail;
tail = tempNode;
tail.setNext(null);
size--;
return tempNode2.getElement();
}
public void remove(E element){
int index = 0;
boolean found = false;
Node<E> temp = head;
for(int i=1; i<=size; i++) {//find the node with element
index++;
if(temp.getElement().equals(element)){
found = true;
break;
}
temp = temp.getNext();
}
if(found){
if(index == 1)
removeFirst();
else if(index == size)
removeLast();
else{
//find the previous node
Node<E> prev = head;
for(int i=1; i<index-1; i++) {
prev = prev.getNext();
}
prev.setNext(temp.getNext());
temp.setNext(null);
size--;
}
}
}
public int searchList(E searchKey) {
if(size == 0)
return -1;
Node tempNode = head;
for(int i=1; i<=size; i++) {
if(tempNode.getElement().equals(searchKey))
return i; //return index of the node
tempNode = tempNode.getNext();
}
return -1; //not found
}
public void printList() {
Node tempNode = head;
for(int i=1; i<=size; i++) {
System.out.print(tempNode.getElement());
if(i!=size) //if it is not last element
System.out.print(" - ");
tempNode = tempNode.getNext();
}
System.out.println();
}
Person class:
public class Person
{
private String name;
private String surname;
private String address;
private PhoneNumber phone1;
private PhoneNumber phone2;
private PhoneNumber phone3;
public Person()
{
name = null;
surname = null;
address = null;
phone1.setPhone(0);
phone1.setType("");
phone2.setPhone(0);
phone2.setType("");
phone3.setPhone(0);
phone3.setType("");
}
public Person(String n, String s, String a,PhoneNumber p1, PhoneNumber p2, PhoneNumber p3)
{
name = n;
surname = s;
address = a;
phone1 = p1;
phone2 = p2;
phone3 = p3;
}
public String getName()
{
return name;
}
public void setName(String n)
{
name = n;
}
public String getSur()
{
return surname;
}
public void setSur(String s)
{
surname = s;
}
public void insertPhone(PhoneNumber phone)
{
if(phone2 == null)
phone2 = phone;
else if(phone3 == null)
phone3 = phone;
}
public PhoneNumber getPhone1()
{
return phone1;
}
public PhoneNumber getPhone2()
{
return phone2;
}
public PhoneNumber getPhone3()
{
return phone3;
}
public String getAdd()
{
return address;
}
public void setAdd(String a)
{
address = a;
}
To sort an Object by its property, you have to make the Object implement the Comparable interface and override the compareTo() method. Lets see the new Fruit class again. The new Fruit class implemented the Comparable interface, and overrided the compareTo() method to compare its quantity property in ascending order.
Definition and Usage. The compareTo() method compares two strings lexicographically. The comparison is based on the Unicode value of each character in the strings. The method returns 0 if the string is equal to the other string.
The compareTo() method works by returning an int value that is either positive, negative, or zero. It compares the object by making the call to the object that is the argument. A negative number means that the object making the call is “less” than the argument.
You can make your Person
class implement Comparable
, and define the following method:
public class Person implements Comparable<Person> {
// Your previous code
public int compareTo(Person other) {
if (other == null) {
// throw exception for example
}
return this.name.toLowerCase().compareTo(other.name.toLowerCase());
}
}
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