Sort list of strings ignoring upper/lower case

Question

I have a list which contains strings representing animal names. I need to sort the list. If I use sorted(list), it will give the list output with uppercase strings first and then lowercase.

But I need the below output.

Input:

var = ['ant','bat','cat','Bat','Lion','Goat','Cat','Ant'] 

Output:

['ant', 'Ant', 'bat', 'Bat', 'cat', 'Cat', 'Goat', 'Lion'] 

Answer 1

The sort() method and the sorted() function take a key argument:

var.sort(key=lambda v: v.upper()) 

The function named in key is called for each value and the return value is used when sorting, without affecting the actual values:

>>> var=['ant','bat','cat','Bat','Lion','Goat','Cat','Ant'] >>> sorted(var, key=lambda v: v.upper()) ['ant', 'Ant', 'bat', 'Bat', 'cat', 'Cat', 'Goat', 'Lion'] 

To sort Ant before ant, you'd have to include a little more info in the key, so that otherwise equal values are sorted in a given order:

>>> sorted(var, key=lambda v: (v.upper(), v[0].islower())) ['Ant', 'ant', 'Bat', 'bat', 'Cat', 'cat', 'Goat', 'Lion'] 

The more complex key generates ('ANT', False) for Ant, and ('ANT', True) for ant; True is sorted after False and so uppercased words are sorted before their lowercase equivalent.

See the Python sorting HOWTO for more information.