I have following array of objects:
[{
id: 1,
amount: 2000,
date: "2018-01-31T00:00:00.000Z"
},{
id: 2,
amount: 3000,
date: "2017-07-31T00:00:00.000Z"
},{
id: 3,
amount: 6000,
date: "2018-01-31T00:00:00.000Z"
},{
id: 4,
amount: 7000,
date: "2017-01-31T00:00:00.000Z"
},{
id: 5,
amount: 5000,
date: "2017-03-31T00:00:00.000Z"
},{
id: 6,
amount: 3000,
date: "2018-02-22T00:00:00.000Z"
},{
id: 7,
amount: 4500,
date: "2017-01-31T00:00:00.000Z"
}]
I am calling following command to group objects by year and date:
_(data)
.groupBy(o => new Date(o.date).getFullYear() + '-' + new Date(o.date).getMonth())
.map(o1 => _(o1).map(o2 => o2.amount).sum())
Code above give me array of sums like [xx, yy, aaa, bbb, ...]
Now I need ensure that these values in array will be ordered (sum of 2018-2 will be first, and sum of 2017-1 will be on the end).
Also will be nice when result will be contains array of sorted objects as I describe above, where each object will be contains also period key "year-month" to detect what current value is. Expected output will be something like this:
[
{period: "2018-2", amount:3000}, // sum of 2018-2
{period: "2018-1", amount: 8000 }, // sum of 2018-1
{period: "2017-7", amount: 3000} // sum of 2017-7
{period: "2017-3", amount: 5000} // sum of 2017-3
{period: "2017-1" amount: 11500} // sum of 2017-1
]
Is possible edit this chain to get required result please? Thanks!
You can use the function reduce along with the function Object.values
Just vanilla javascript
var data = [{ id: 1, amount: 2000, date: "2018-01-31T00:00:00.000Z"},{ id: 2, amount: 3000, date: "2017-07-31T00:00:00.000Z"},{ id: 3, amount: 6000, date: "2018-01-31T00:00:00.000Z"},{ id: 4, amount: 7000, date: "2017-01-31T00:00:00.000Z"},{ id: 5, amount: 5000, date: "2017-03-31T00:00:00.000Z"},{ id: 6, amount: 3000, date: "2018-02-22T00:00:00.000Z"},{ id: 7, amount: 4500, date: "2017-01-31T00:00:00.000Z"}];
var result = Object.values(data.reduce((a, c) => {
var [year, month] = c.date.split('-');
var key = `${year}-${+month}`;
(a[key] || (a[key] = {period: key, amount: 0})).amount += c.amount;
return a;
}, {})).sort((a, b) => b.period.localeCompare(a.period));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
You could get the grouped data and sort it ascending (the only possible way with lodash) and reverse the order.
var data = [{ id: 1, amount: 2000, date: "2018-01-31T00:00:00.000Z" }, { id: 2, amount: 3000, date: "2017-07-31T00:00:00.000Z" },{ id: 3, amount: 6000, date: "2018-01-31T00:00:00.000Z" }, { id: 4, amount: 7000, date: "2017-01-31T00:00:00.000Z" }, { id: 5, amount: 5000, date: "2017-03-31T00:00:00.000Z" }, { id: 6, amount: 3000, date: "2018-02-22T00:00:00.000Z" }, { id: 7, amount: 4500, date: "2017-01-31T00:00:00.000Z" }],
result = _(data)
.groupBy(o => o.date.slice(0, 7))
.map((array, sort) => ({ sort, date: sort.split('-').map(Number).join('-'), amount: _.sumBy(array, 'amount') }))
.sortBy('sort')
.reverse()
.map(({ date, amount }) => ({ date, amount }))
.value();
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.15.0/lodash.min.js"></script>
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