Sort array in Czech, localeCompare

Question

I have problem sorting an array with Czech names. It works ok for the normal characters but not for the special ones. 'Sb', 'St', 'Šk' ; the special Š should be after the other two words, but it end it up in different order. Here is a simple code.

var tmpArr = ['Sb', 'BE', 'De', 'CS', 'Au', 'Šk', 'De', 'St', 'Ci', 'št'];

function mySort(s1, s2) {
return s1.localeCompare(s2 ,'cz', {sensitivity: "variant"});
}

var sorted = tmpArr.sort(mySort);

console.log(tmpArr);

for(var i in sorted){
console.log(sorted[i]);
}

This should be also working in all browsers.

Answer 1

Dobrý Den,

as this states

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/localeCompare

advanced options for locale compare are not implemented in common browsers.

If you need this only for Chech language maybe it would be best idea to implement your own string comparison using characters map:

var charMapL = " 0123456789aábcčdďeéěfghiíjklmnňoópqrřsštťuúůvwxyýzž";
var charMapU = " 0123456789AÁBCČDĎEÉĚFGHIÍJKLMNŇOÓPQRŘSŠTŤUÚŮVWXYÝZŽ";
var charsOrder = {};
for(var i in charMapL.split('')) {
    charsOrder[charMapL[i]] = parseInt(i);
    charsOrder[charMapU[i]] = parseInt(i);
}

function mySort(s1, s2) {
    var idx = 0;
    while ( (idx < s1.length) && (idx < s2.length) && (charsOrder[s1[idx]] == charsOrder[s2[idx]])) {
        idx ++;
    }
    if ((idx == s1.length) && (idx == s2.length)) return 0;
    if (idx == s1.length) return 1;
    if (idx == s2.length) return -1;
    return charsOrder[s1[idx]] > charsOrder[s2[idx]] ? 1 : (charsOrder[s1[idx]] < charsOrder[s2[idx]] ? -1 : 0);
}

console.log(tmpArr);
tmpArr.sort();
console.log(tmpArr);
tmpArr.sort(mySort);
console.log(tmpArr);

http://jsfiddle.net/GNNBc/1/