Sort an object array by custom order

Question

I have an array of objects which have a property called 'CODE'.

[
  {
   ID: 168,
   NAME: "First name",
   CODE: "AD"
  },
  {
   ID: 167,
   NAME: "Second name",
   CODE: "CC"
  },
  {
   ID: 169,
   NAME: "Third name",
   CODE: "CCM"
  },
  {
   ID: 170,
   NAME: "Fourth name",
   CODE: "CR"
  },
]

How do I order the array by a customized order like:

var item_order = ["CCM","CR","AD","CC"];

Been trying various methods with no success. Please help.

Answer 1

You can use the function sort along with the function indexOf.

var array = [  {   ID: 168,   NAME: "First name",   CODE: "AD"  },  {   ID: 167,   NAME: "Second name",   CODE: "CC"  },  {   ID: 169,   NAME: "Third name",   CODE: "CCM"  },  {   ID: 170,   NAME: "Fourth name",   CODE: "CR"  }],
    item_order = ["CCM","CR","AD","CC"];

array.sort((a, b) => item_order.indexOf(a.CODE) - item_order.indexOf(b.CODE));

console.log(array);

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Answer 2

For huge arrays, I suggest to use an object for the indices.

var array = [{ ID: 168, NAME: "First name", CODE: "AD" }, { ID: 167, NAME: "Second name", CODE: "CC" }, { ID: 169, NAME: "Third name", CODE: "CCM" }, { ID: 170, NAME: "Fourth name", CODE: "CR" }],
    item_order = ["CCM", "CR", "AD", "CC"],
    order = item_order.reduce((r, k, v) => Object.assign(r, { [k]: v }), {});

array.sort((a, b) => order[a.CODE] - order[b.CODE]);

console.log(array);

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