Sort an array of objects in typescript?

Question

How do I sort an array of objects in TypeScript?

Specifically, sort the array objects on one specific attribute, in this case nome ("name") or cognome ("surname")?

/* Object Class*/ export class Test{      nome:String;      cognome:String; }  /* Generic Component.ts*/ tests:Test[]; test1:Test; test2:Test;  this.test1.nome='Andrea'; this.test2.nome='Marizo'; this.test1.cognome='Rossi'; this.test2.cognome='Verdi';  this.tests.push(this.test2); this.tests.push(this.test1); 

thx!

Answer 1

It depends on what you want to sort. You have standard sort funtion for Arrays in JavaScript and you can write complex conditions dedicated for your objects. f.e

var sortedArray: Test[] = unsortedArray.sort((obj1, obj2) => {     if (obj1.cognome > obj2.cognome) {         return 1;     }      if (obj1.cognome < obj2.cognome) {         return -1;     }      return 0; }); 

Answer 2

Simplest way for me is this:

Ascending:

arrayOfObjects.sort((a, b) => (a.propertyToSortBy < b.propertyToSortBy ? -1 : 1)); 

Descending:

arrayOfObjects.sort((a, b) => (a.propertyToSortBy > b.propertyToSortBy ? -1 : 1)); 

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In your case, Ascending:

testsSortedByNome = tests.sort((a, b) => (a.nome < b.nome ? -1 : 1)); testsSortedByCognome = tests.sort((a, b) => (a.cognome < b.cognome ? -1 : 1)); 

Descending:

testsSortedByNome = tests.sort((a, b) => (a.nome > b.nome ? -1 : 1)); testsSortedByCognome = tests.sort((a, b) => (a.cognome > b.cognome ? -1 : 1));